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andrew-mc [135]
3 years ago
7

Given that the points (-1,6). (3,6), (3, 1), and (-1, 1) are vertices of a rectangle, how much shorter is the width than the len

gth?
Mathematics
1 answer:
Ksju [112]3 years ago
6 0
Since the given coordinates are already in order,
then and two consecutive distances between the coordinates will give length and breadth,

Using distance formula,
\sqrt{ {( - 1 - 3)}^{2}  +  {(6 - 6)}^{2} }  \\  =  \sqrt{ { (- 4)}^{2} }  \\  =  \sqrt{16 }  \\  = 4
(we'll not consider the negative value since distances can't be negative)

Applying this again on 2nd and 3rd coordinates,
\sqrt{ {(3 - 3)}^{2} +  {(6 - 1)}^{2}  }  \\  =  \sqrt{ {5}^{2} }  \\  = 5
(we'll not consider the negative value since distances can't be negative)

Since length's always gotta be greater than bredth
therefore,
the difference will be 5-4= 1 units


Hence width is 1 unit shorter than length.



Note: Unit used is "unit/s"
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Can anyone help me solve this
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Answer:

a. $45.54; b. $51.42; c. See below

Step-by-step explanation:

a. 193 min

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which we can write like this:

f(t) =\begin{cases}40.00 + 0.021t & t \leq 100\\42.10 + 0.037(t-100) & 100 < t \leq200\\45.80 + 0.048(t-200) & t > 200\end{cases}

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We assume your intensity function is ...

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