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seraphim [82]
3 years ago
11

Which of the following lists of ordered pairs is a function? A. (2, 4), (0, 2), (2, -4), (5, 3) B. (1, 2), (1, -2), (3, 2), (3,

4) C. (0, 2), (2, 3), (0, -2), (4, 1) D. (1, 6), (2, 7), (4, 9), (0, 5)
Mathematics
2 answers:
Blababa [14]3 years ago
8 0
B
..........................
Angelina_Jolie [31]3 years ago
4 0
D.
Because a function has to pass the "vertical line test" meaning that no two points can have the same X value
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Express the following in p/q form, where p and q are integers and q is not equal to 0.
Wewaii [24]
(I)1.272727... = 14/11
(II)0.1282828...= 127/990

(The solution is in the picture
NB : the two points on the two numbers in the solution means those two numbers are recurring or repeating )

5 0
3 years ago
Please help answer and explanation its my final
Nookie1986 [14]

Answer:

0/6 because the arrow start from zero and end at six, remember that the arrow is starting from the vertical axis.....

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3 years ago
What is the answer to x-5?
Thepotemich [5.8K]

Answer: x=5

Step-by-step explanation:

i’m not sure if that’s what you meant. there’s not much info.

8 0
3 years ago
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An online furniture store sells chairs for $150 each and tables for $400 each. Every day, the store can ship no more than 30 pie
ivolga24 [154]

Answer:

minimum of 13 chairs must be sold to reach a target of $6500

and a max of 20 chairs can be solved.

Step-by-step explanation:

Given that:

Price of chair = $150

Price of table = $400

Let the number of chairs be denoted by c and tables by t,

According to given condition:

t + c = 30 ----------- eq1

t(150) + c(400) = 6500 ------ eq2

Given that:

10 tables were sold so:

t = 10

Putting in eq1

c = 20 (max)

As the minimum target is $6500 so from eq2

10(150) + 400c = 6500

400c = 6500 - 1500

400c = 5000

c = 5000/400

c = 12.5

by rounding off

c = 13

So a minimum of 13 chairs must be sold to reach a target of $6500

i hope it will help you!

4 0
3 years ago
Part 1: Identify key features and graph a parabola from standard form.
astraxan [27]

Wait i will tell you soon dont worry, im out now sorryy ^.^

4 0
3 years ago
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