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Mandarinka [93]
2 years ago
13

WHAT IS THE VALUE OF THE EXPRESSION 8 MORE THEN 3 TIMES THE DIFFRENCE OF 4 AND A NUMBER WHEN N=3

Mathematics
1 answer:
kogti [31]2 years ago
6 0

The value of the expression as described in the task content is; 11.

<h3>What is the value of the expression?</h3>

The expression as described in the task content is; 3(4 - N) +8.

However, the value of N in this scenario is; 3.

Therefore, the value of.the expression is;

3(4 - 3) +8

= 3(1) + 8

= 3+8

= 11.

Read more on value of expressions;

brainly.com/question/625174

#SPJ1

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Will mark as brainiest answer!!!!!<br> Please show work as to how you found the answer
Alchen [17]
(2,8) and (-2,10)

<u>y₂</u><u> </u><u>- y₁</u>     used to find the slope<u>
</u>x₂ - x₁
<u>
</u>plug in the coordinates
<u>10-8</u> = <u>2</u>     all equals -1/2
-2-2 = -4     m=-1/2
<u>
</u>plug one of the coordinates and the slope into y=mx+b, and solve
<u />8=-1/2(2)+b
8=-1+b
9=b

Final Answer: y = -1/2x + 9
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3 years ago
In the cube shown below, the distance between vertices 2 and 6 is 15 cm.
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45 squared centimeters
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3 years ago
Read 2 more answers
Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.
barxatty [35]

Answer:

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx

If f(x) = 7 +10\cdot x - 9\cdot x^{2}, a = 0, b = b and \bar f = 8, then:

\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8

\frac{7}{b}\int\limits^b_0 \, dx  + \frac{10}{b}  \int\limits^b_0 {x}\, dx - \frac{9}{b}  \int\limits^b_0 {x^{2}}\, dx = 8

\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8

7 + 5\cdot b - 3\cdot b^{2} = 8

3\cdot b^{2}-5\cdot b +1 = 0

The roots of this polynomial are determined by the Quadratic Formula:

b_{1} \approx 1.434 and b_{2} \approx 0.232.

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

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