All categories

3 years ago

I cannot figure out the work for this problem.

1 answer:

8 0

Your answer should be -2
Use PEMDAS if confused!
Parentheses
Exponent
Multiplication
Division
Addition
Subtraction.
You would first calculate the number in between your parentheses which would give you -1. Then do -1 to the power of 4(-1^4) which still gives you -1 and then multiply it by 2 which should give you your answer -2. :)
Hope this helps.

You might be interested in

Find the equation for the line

saveliy_v [14]

Answer:

6/4

Step-by-step explanation:

5 0

3 years ago

Divide. Give the quotient and remainder. 8÷2,8218

GuDViN [60]

The answer is 4/14109 or 0.00028350 as a decimal

8 0

4 years ago

A scale drawing of a living room is shown below.

prisoha [69]

Answer:

A=80 square feet.

Step-by-step explanation:

First, we find the area of the model. 6*4=24. Now, due to the ratio of 1:40, we know that every inch is actually forty inches. So, you do this:

24*40=960.

So, the area of the actual living room is 960 inches. Or 80 feet.

3 0

4 years ago

370 people bought tickets to a fair. Adult tickets were $7 and kids tickets were $3. Total revenue was $1750. Child tickets are

galina1969 [7]

210 children tickets are sold

Solution:

Let "x" be the number of child tickets sold

Let "y" be the number of adult tickets sold

Cost of 1 adult ticket = $ 7

Cost of 1 child ticket = $ 3

Given that 370 people bought tickets to a fair

number of child tickets sold + number of adult tickets sold = 370

x + y = 370 ------ eqn 1

Total revenue was $1750. Therefore,

number of child tickets sold x Cost of 1 child ticket + number of adult tickets sold x Cost of 1 child ticket = 1750

$x \times 3 + y \times 7 = 1750$

3x + 7y = 1750 ------ eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

x = 370 - y ------- eqn 3

Substitute eqn 3 in eqn 2

3(370 - y) + 7y = 1750

1110 - 3y + 7y = 1750

4y = 1750 - 1110

4y = 640

From eqn 3,

x = 370 - 160

Thus 210 children tickets are sold

7 0

3 years ago

If sin θ = 2 over 7 and tan θ > 0, what is the value of cos θ?

sashaice [31]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\quad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin(\theta )=\cfrac{2}{7}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{7^2-2^2}=a\implies \pm\sqrt{45}=a\implies \pm 3\sqrt{5}=a$

but.... which is it? the + or the -? well, we know that tan(θ) > 0, is another way to say that the tangent of the angle is positive, now, for the tangent to be positive, since it's opposite/adjacent both opposite and adjacent have to be the same exact sign, now, we know the opposite is +2, so that means the adjacent has to be the same sign, thus is the positive version 3√(5)

thus $\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\qquad \qquad cos(\theta )=\cfrac{3\sqrt{5}}{7}$

3 0

4 years ago