5x+9 =14
14 -6=8
8•2 = 14
So they answer is 14
A meter is 100 cm. So, the final length is
![1\frac{1}{2}*100=\frac{3}{2}*100=\frac{300}{2}=150](https://tex.z-dn.net/?f=1%5Cfrac%7B1%7D%7B2%7D%2A100%3D%5Cfrac%7B3%7D%7B2%7D%2A100%3D%5Cfrac%7B300%7D%7B2%7D%3D150)
cm.
150 cm.
Answer:
divide 88 by the number of x
88/8= 11
X = 11
Answer:
3) 0.30
The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given 'A' plays a sport
B work part time
Given P(A) = 0.48
P(B) = 0.40
P(A∩B) =0.12
P(A∪B)¹ =0.24
<u><em>Step(ii)</em></u>:-
By using conditional probability
![P(B/A) = \frac{P(BnA}{P(A)}](https://tex.z-dn.net/?f=P%28B%2FA%29%20%3D%20%5Cfrac%7BP%28BnA%7D%7BP%28A%29%7D)
and similarly ![P(A/B) = \frac{P(AnB}{P(B)}](https://tex.z-dn.net/?f=P%28A%2FB%29%20%3D%20%5Cfrac%7BP%28AnB%7D%7BP%28B%29%7D)
The probability a randomly selected<em> student plays a sport</em> given they work part time
Now ![P(A/B) = \frac{P(AnB}{P(B)}](https://tex.z-dn.net/?f=P%28A%2FB%29%20%3D%20%5Cfrac%7BP%28AnB%7D%7BP%28B%29%7D)
![P(A/B) = \frac{0.12}{0.40}= 0.30](https://tex.z-dn.net/?f=P%28A%2FB%29%20%3D%20%5Cfrac%7B0.12%7D%7B0.40%7D%3D%200.30)
<u>Final answer</u>:-
The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30