Answer : easy try yourself I hope you can
I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])
Answer:
y=1/2x-1
Step-by-step explanation:
-4y=4-2x
4y=4-2x
y=-1+1/2x
y=1/2x-1
Answer:
I believe it is right by looking at this picture, but I am not certain