For a better understanding of the explanation provided here kindly go through the file attached.
Since, the weight attached is already at the lowest point at time, t=0, therefore, the equation will have a -9 as it's "amplitude" and it will be a Cosine function. This is because in cosine function, the function has the value of the amplitude at t=0.
Now, we know that the total angle in radians covered by a cosine in a given period is
and the period given in the question is t=3 seconds. Therefore, the angular velocity,
of the mentioned system will be:

Combining all the above information, we see that the equation which models the distance, d, of the weight from its equilibrium after t seconds will be:

Thus, Option B is the correct option. The attached diagram is the graph of the option B and we can see clearly that at t=3, the weight indeed returns to it's original position.
Answer:
2x-1=0
Step-by-step explanation:
x-0.5=0
10x-5=0
2x-1=0
Answer:
2n=10
Step-by-step explanation:
Distribute the 2 to each term. 2xn=2n and 2x5=10. then you put them together.
Answer:
7/21
Step-by-step explanation: