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blsea [12.9K]
3 years ago
7

-3k + 3(k - 6) = 18 Help please!!!

Mathematics
1 answer:
vovangra [49]3 years ago
4 0
No solution for this question
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En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz
nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

             = 180° - 72° - 64°

             = 44°  

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

                  = 180° - 90° - 72°

                  = 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

                  = 180° - 18° - 36°

                  = 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

                  = 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

                  = 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

                  = 180° - 14° - 54°  

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

<em>d</em> = angle BQP - angle PBQ

  = 112° - 14°

  = 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

4 0
3 years ago
(−6)^2<br> Need halp please
ziro4ka [17]
This is an EXPONENT. 

To do this all we need to do is multiply the base by itself how many times the power says.

(-6)² = (-6) × (-6) = 36

Recall that any negative number times another negative number is positive so that is why this would be positive.  

So, (-6)² = 36

Hope I helped ya!! 
4 0
3 years ago
Read 2 more answers
PLEASE HELP ME SOLVE THIS Find all x-values for which f ( x ) = 2 for the function below.
alisha [4.7K]

Answer:

<h3>x = -3</h3>

Step-by-step explanation:

First let us get the equation of the coordinates

y-y0 = m(x-x0)

Using the coordinates ( - 3, 2 ), ( - 1, 0 )

m = 0-2/-1-(-3)

m = -2/2

m = -1

Substitute m = -1 and (-1, 0) into the formula

y - 0 = -1(x+1)

y = -x-1

f(x) = -x-1

Since f(x) = 2

2 = -x-1

-x = 2+1

-x = 3

x = -3

Hence the value of x is -3

3 0
3 years ago
It costs $100 to join a fitness center plus a monthly fee. You spent $700 last year at the fitness center. How much was the mont
Virty [35]

It cost $50 a month


Work: 700 - 100 = 600

600 / 12 = 50


Hope this helps!

6 0
3 years ago
Read 2 more answers
What is the arc measure of AEB in degrees
jasenka [17]

Answer:

305 degree

Step-by-step explanation:

As AD and CE are the diameters of circle P, so that they intersect each other at point P.

=> So that ∡CPA and ∡DPE are two vertical angles.

=> ∡CPA = ∡DPE = 93 degree

As we can see, ∡CPA = ∡CPB + ∡BPA =38 + ∡BPA

=> ∡BPA = ∡CPA - 38 = 93 - 38 = 55 degree

As P is the centre of the circle, so that ∡BPA is equal to the measure of the arc AB, equal to 55 degree.

In the circle P, the total measure of arc AEB and arc AB are 360 degree

=> arc AEB + arc AB = 360

=> arc AEB = 360 - arc AB = 360 - 55 = 305

So that the measure of arc AEB is 305 degree

7 0
3 years ago
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