3 years ago

A circle has the equation x^2+y^2+x-6y+9=0. Find the center and any x or y intercepts.

Mathematics

1 answer:

Softa [21]3 years ago

5 0

We know:x^2+y^2+x−6y+9=0So, we complete the square as such:x^2+y^2+x−6y+9=x^2+x+y^2−6y+9=(x+1/2)^2+(y−3)^2=(1/2)^2=1/4

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