You just add the lengths of RS and ST together. In your case RT= 24
The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.
<h3>Quadratic equation</h3>
8x² + 16x + 3 = 0
8x² + 16x = -3
8(x² + 2x) = -3
- Using completing the square
8(x² + 2x + 1) = -3 + 8
8(x² + 1) = 5
(x² + 1) = 5/8
- Taking the square root of both sides
(x + 1) = ± √5/8
x = -1 ± √5/8
Therefore,
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
Learn more about quadratic equation:
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Answer:
Explanation:
Use the Pythagorean theorem (
a
2
+
b
2
=
c
2
)
Lets label the right triangle such that:
a
=
12
b
=
16
c
=
x
Thus,
12
2
+
16
2
=
x
2
144
+
256
=
x
2
400
=
x
2
√
400
=
x
20
=
x
So our missing side,
c
is
20
We can now say that the sides of our triangle are
12
,
16
,
20
I've included a link that lists a couple of Pythagorean triples (a couple because they are infinitely many).
Step-by-step explanation:
Hope it helpful
Answer:
"absolute value function," y = |x|
Step-by-step explanation:
This is the graph of the "absolute value function," y = |x|.
Answer:Im pretty sure it's 25% percent loss
Step-by-step explanation:
sorry if im wrong
