There is only one statement that is true: B. The graph of the function is a parabola.
<h3>How to study and interpret the characteristics of quadratic equations</h3>
In this question we have a <em>quadratic</em> equation, whose characteristics have to be inferred and analyzed. We need to prove each of the five choices presented in the statement:
Choice A:
If we know that x = - 10, then we evaluated it at the function:
f(- 10) = (- 10)² - 5 · (- 10) + 12
f(- 10) = 162
False
Choice B:
By analytical geometry we know that all functions of the form y = a · x² + b · x + c always represent parabolae.
True
Choice C:
The <em>quadratic</em> function opens up as its <em>leading</em> coefficient is greater that 0.
False
Choice D:
If we know that x = 20, then we evaluate it at the function:
f(20) = 20² - 5 · (20) + 12
f(20) = 312
False
Choice E:
If we know that x = 0, then we evaluate it at the function:
f(0) = 0² - 5 · (0) + 12
f(0) = 12
There is only one statement that is true: B. The graph of the function is a parabola.
To learn more on quadratic equations: brainly.com/question/1863222
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Answer:
The equation of the perpendicular line would be y = -2/5x - 1
Step-by-step explanation:
In order to find this line, we must first find the slope of the original line. We do this by solving for y.
-5x + 2y = -10
2y = 5x - 10
y = 5/2x - 5
This shows us a slope of 5/2. TO find the perpendicular slope, we use the opposite and reciprocal. This means we negative 5/2 to get -5/2 and then we flip it to get -2/5. Now that we have this, we can use the slope and the point in point-slope form to get the equation.
y - y1 = m(x - x1)
y - 1 = -2/5(x + 5)
y - 1 = -2/5x - 2
y = -2/5x - 1
Answer:
6.2813
Step-by-step explanation:
If you minus 27.31 of 23%. 23% would have to be changed into a decimal or whole number.
After that, you would want to check your answer on a calculator, which I usually do.
<span>Use the order of operation, PEMDAS.
6²÷2(3) +4
36/2(3)+4
=(18)(3)+4
=54+4
=58</span>
Step-by-step explanation:
in the textbook column you can find the search symbol
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