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3 years ago

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Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

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What exactly are you asking? Please elaborate.

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Select the correct answer from each drop-down menu. A self-service car wash charges $4 for the initial 5 minutes plus an additio

arlik [135]

Answer: For $m\geq15$

$\\\Rightarrow\ y=4+0.75(m-5)\geq4+0.75(15-5)\\\Rightarrow\ y\geq4+0.75(10)\\\Rightarrow\ y\geq4+7.5\\\Rightarrow\ y\geq11.5$

Nick does not has enough money to follow this recommendation.

Step-by-step explanation:

Given: A self-service car wash charges $4 for the initial 5 minutes plus an additional $0.75 for each minute after that.

Let y be the cost for car wash for m minutes then

$y=4+0.75(m-5)$ such that at m= 5 , y=4 which is the cost for car wash (dollars) for first 5 minutes.

Also, A car enthusiast magazine recommends spending at least 15 minutes to properly wash a car.

For $m\geq15$

$\\\Rightarrow\ y=4+0.75(m-5)\geq4+0.75(15-5)\\\Rightarrow\ y\geq4+0.75(10)\\\Rightarrow\ y\geq4+7.5\\\Rightarrow\ y\geq11.5$

But Nick has $10 which is less than $11.5, so he does not has enough money to follow this recommendation.

7 0

3 years ago

Read 2 more answers

Which statement is correct?

Arisa [49]

Answer:

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

$206 \times 18.8 = 3,872.8$

$7.69 \times 10^-^2 = 769$

$2.3 \times 10^-^5 = 230,000$

$=\frac{769}{230000}$

= 0.00334

therefore,

3,872.80 > 0.00334

Step-by-step explanation:

Which statement is correct?

(2.06x102x1.88 x 10-1) <7.69x 10

2.3x10-5

(2.06 x 10-2)(1.88 x 10-1) 7.69x 10-

2.3x10-5

7.69 x 10"

(2.06 x 10-2x1.88x10-)>

2.3x10-5

(2.06x 10-2X(1.88x 10-1)-7.69x104

2.3x10-5

Given that;

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

$206 \times 18.8 = 3,872.8$

$7.69 \times 10^-^2 = 769$

$2.3 \times 10^-^5 = 230,000$

$=\frac{769}{230000}$

= 0.00334

therefore,

3,872.80 > 0.00334

7 0

3 years ago

Write a equation of a hyperbola given the foci and the asymptotes

professor190 [17]

Solution:

The standard equation of a hyperbola is expressed as

$\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}$

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}$

The asymptote of n hyperbola is expressed as

$y=\pm\frac{a}{b}(x-h)+k$

Given that the asymptotes are

$y=\frac{3}{4}x\text{ and y=-}\frac{3}{4}x$

This implies that

$a=3,\text{ and b=4}$

To evaluate the value of h and k,

$undefined$

3 0

1 year ago

Can sum1 hurry and give me the answers to theses pls !!

suter [353]

Answer:

i dont understand what you want us to do lol?

Step-by-step explanation:

6 0

2 years ago

A home has a triangular backyard. The second angle of the triangle is 6º more than the first angle. The third angle is 14º more

Leto [7]

Answer:

The three angles of the triangle are 40, 45, and 95. Done.

4 0

2 years ago