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Sonbull [250]
2 years ago
9

Mary wants to fill in a cylinder vase. At the flower store they told her that the vase should be filled 3/4 for the flowers to l

ast the longest. Her cylinder vase has a radius of 2 inches and a height of 9in. How much water should Mary pour into the vase
Mathematics
1 answer:
dangina [55]2 years ago
6 0
1.5 width and hmm... 6.8 height?
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How to you solve -15=y-62
sdas [7]
First move the (Y) to the other side of the equal sign,
- y - 15 = - 62
Then subtract add (15) on both sides
- y = - 47
Since a variable can't be negative just divide by (-1) on both sides,
\frac{ - y}{ - 1} = \frac{ - 47}{ - 1}
The answer would be,
y = 47
Hope this helped
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7 0
2 years ago
Please help me with the below question.
Snezhnost [94]

6a. By the convolution theorem,

L\{t^3\star e^{5t}\} = L\{t^3\} \times L\{e^{5t}\} = \dfrac6{s^4} \times \dfrac1{s-5} = \boxed{\dfrac5{s^4(s-5)}}

6b. Similarly,

L\{e^{3t}\star \cos(t)\} = L\{e^{3t}\} \times L\{\cos(t)\} = \dfrac1{s-3} \times \dfrac s{1+s^2} = \boxed{\dfrac s{(s-3)(s^2+1)}}

7. Take the Laplace transform of both sides, noting that the integral is the convolution of e^t and f(t).

\displaystyle f(t) = 3 - 4 \int_0^t e^\tau f(t - \tau) \, d\tau

\implies \displaystyle F(s) = \dfrac3s - 4 F(s) G(s)

where g(t) = e^t. Then G(s) = \frac1{s-1}, and

F(s) = \dfrac3s - \dfrac4{s-1} F(s) \implies F(s) = \dfrac{\frac3s}{\frac{s+3}{s-1}} = 3\dfrac{s-1}{s(s+3)}

We have the partial fraction decomposition,

\dfrac{s-1}{s(s+3)} = \dfrac13 \left(-\dfrac1s + \dfrac4{s+3}\right)

Then we can easily compute the inverse transform to solve for f(t) :

F(s) = -\dfrac1s + \dfrac4{s+3}

\implies \boxed{f(t) = -1 + 4e^{-3t}}

6 0
1 year ago
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jwjwhbahauiwbsbbdvwhwuusg

5 0
3 years ago
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Evaluate:<br><br> -7 - (-8) + (-3) + 6 - 2<br><br> A) -2 <br> B) 0 <br> C) 1 <br> D) 2
Gala2k [10]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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