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joja [24]
3 years ago
9

A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?

Mathematics
2 answers:
statuscvo [17]3 years ago
8 0
I hope this helps you

Otrada [13]3 years ago
8 0

Answer:

Area of of the doghouse which is in the shape of right trapezoid is 66.5 square feet.

Step-by-step explanation:

Consider a right trapezoid with top side AB is 7 feet and height AD is 7 feet. The bottom side DC is extended to the right with 5 more feet.that is (7+5)  12 feet.

We have to find the area of the doghouse which is in the shape of right trapezoid .

\text{Area of trapezoid}=\frac{1}{2}\times (\text{sum of parallel sides})\times {\text{(Height)}}

that is,

\text{Area of trapezoid}=\frac{1}{2}\times (AB+DC)\times (AD)

Substitute the values, we get,

\text{Area of trapezoid}=\frac{1}{2}\times (7+12)\times 7

\Rightarrow \text{Area of trapezoid}=\frac{1}{2}\times 19\times 7

\Rightarrow \text{Area of trapezoid}=\frac{1}{2}\times 133

\Rightarrow \text{Area of trapezoid}=66.5

Hence, Area of of the doghouse which is in the shape of right trapezoid is 66.5 square feet.

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Answer:

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Step-by-step explanation:

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What is the solution? x=? 2x+3=4x+2
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Read 2 more answers
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