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3 years ago

15

Tony is going to watch a movie in his collection. He has 3 action movies, 11 comedies, and 9 dramas. He will randomly select one

movie. What is the probability that the movie he selects is not a comedy?
Write your answer as a fraction in simplest form.

1 answer:

Nata [24]3 years ago

4 0

Answer:

12/23

Step-by-step explanation:

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Simplify the expression 3x(x – 12x) + 3x2 – 2(x – 2)2. Which statements are true about the process and simplified product? Check

kirill115 [55]

Given: The algebraic expression 3x(x – 12x) + 3x² – 2(x – 2)² --------(i)

To prove: The final simplified product = –28x² +8x – 8.

Solution:

Step No. 1

First, we shall expand the term (x – 2)² by using Identity (a-b)²= a² + b² - 2ab

So, (x – 2)² = x² + 4 - 4x

From given expression (i)

3x(x – 12x) + 3x² – 2(x² + 4 - 4x) --------(ii)

Step No. 2

Now, we shall multiply by the terms within the parentheses in (ii)

(3x² – 36x²) + 3x² – (2x² + 8 - 8x) --------(iii)

Step No. 3

Now, we shall simplify the terms within the parentheses in (iii)

(– 33x²) + 3x² – (2x² + 8 - 8x) --------(iv)

Step No. 4

Now, we shall open the parentheses to eliminate parentheses in (iv)

– 33x² + 3x² – 2x² - 8 + 8x --------(v)

Step No. 5

Now, we shall add and subtract the like terms in (v)

– 28x² + 8x -8 --------(vi)

Hence, the simplified expression will be – 28x² + 8x -8

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I'm Chloe can you help me, Thanks :)

Nostrana [21]

Answer:

Hola losiento no se ablar inglés

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2 years ago

Can someone help me on questions 10-15

Mazyrski [523]

Answer:

10. Supplementary

11. Congruent

12. Congruent.

13 . congruent

14 supplement

15 supplementary

<h3>Hope this helps you </h3><h3>Do mark as brainliest! </h3>

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The figure below shows a straight line AB intersected by another straight line t:

BaLLatris [955]

When two straight lines intersect, the pairs of nonadjacent angles in opposite posi-tions are known as vertical angles.

If a segment AB is intersected by a transversal labeled t, then ∠1 and ∠3 and ∠2 and ∠4 are vertically angles formed by the transversal t on the segment AB.

Angles ∠1 and ∠2 can be described as adjacent and supplementary angles, so

$m\angle 1+m\angle 2=180^{\circ}$ .

Angles ∠3 and ∠2 can be also described as adjacent and supplementary angles, so

$m\angle 3+m\angle 2=180^{\circ}$ .

Subtract from the first equation the second equation:

$m\angle 1+m\angle 2-(m\angle 3+m\angle 2)=180^{\circ}-180^{\circ},\\ m\angle 1-m\angle 3=0,\\ m\angle 1=m\angle 3$ .

Similarly you can prove that $m\angle 2=m\angle 4$ .

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0.1846 as a fraction

GenaCL600 [577]

0.1846 as a fraction=1846\10000

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