3(3)^2 - (-2)^3 - (-2)^3 + 5
27 - (-8) - (-8) +5
35 - (-8) + 5
43 + 5
48
Answer:
By AA
ΔWXY ~ΔWVZ
Step-by-step explanation:
Here WXY is an isosceles triangle with legs WX & WY
So WX = WY
Hence ∠X = ∠Y
So ∠2= ∠3.
Now by angle sum property
∠1 + ∠2+∠3 = 180°
∠1+∠2+∠2=180°
2∠2 = 180° - ∠1 .......(1)
In triangle WVZ
WV = WZ
So ∠V = ∠Z
∠4 = ∠5
Once again by angle sum property
∠1 + ∠4 + ∠5=180°
∠1 + ∠4 + ∠4 = 180°
2∠4 = 180° - ∠1 ...(2)
From (1) & (2)
2∠2 = 2∠4
∠2=∠4
Now ∠W is common to both triangles
Hence by AA
ΔWXY ~ΔWVZ
So you want the totals to be -6 and 10, so for -6, I would do -|3| + -|3|. The negative sign on the outside cancels it out. For 10, you could do |3| + |-7|.
Answer:
47.3
Step-by-step explanation:
Answer:
348
Step-by-step explanation: