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2 years ago

If a car can travel 3,267 miles on 33 gallons of fuel, how many gallons are required to travel 107,811 miles?

Mathematics

1 answer:

CaHeK987 [17]2 years ago

5 0

(107,811 * 33)/3267 = 1089 gallons of fuel

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Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

Step-by-step explanation:

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

4 0

3 years ago

Six plus what equals -2

Rudiy27

Answer: -8

Step-by-step explanation:

6+ -8 = -2

7 0

3 years ago

Mark ran 2 1/3 km and Shaun ran 3 1/5 km. Find the difference in the distance that they ran.

soldier1979 [14.2K]

Answer:

7/15 km

Step-by-step explanation:

Find the least common denominator between the two fractions. The least common denominator in this case would be 15, so you have to multiply 1/3 by 5 to have a denominator of 15. Then you multiply 1/5 by 3 to have a denominator of 15. You will find that Mark ran a distance of 2 5/15 km and Shaun ran 3 3/15 km. To make it even easier, you can add the whole number back into the fraction so Mark will have ran 35/15 km and Shaun will have ran 48/15 km meaning that Shaun will have ran more. Then you set you fractions up and subtract them.

6 0

3 years ago

What is 12. 6 more than twice m algebraic expression

Andreyy89

2m+6
because twice m =2m and 6 more =+6

8 0

3 years ago

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(1/9) × 5 × 3√(2 × (1/arccos(8741)) × 543) =

Nadusha1986 [10]

Answer:

Undifined