1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
masya89 [10]
3 years ago
8

3) Find f(3) for the function below. f(x) = 2x² – 3x

Mathematics
2 answers:
arlik [135]3 years ago
7 0

Answer:

<h2> f(3) = 9</h2>

Step-by-step explanation:

f(x) = 2x^2 -3x\\ f(3) = ?\\\\ f(3) = 2(3)^2 -3(3)\\ f(3) = 2(9) - 9\\ f(3) = 18- 9\\ f(3) = 9

Firdavs [7]3 years ago
5 0

Answer:

9

Step-by-step explanation:

f(x) = 2x² – 3x

Let x=3

f(3) = 2 * 3^2 - 3*3

     = 2 *9 - 9

     = 18-9

      = 9

You might be interested in
What is y=-4/3x +6. y=2
Mekhanik [1.2K]

The given equation is:
[/tex]y=-\frac{4}{3}x+6 [/tex] and we need to evaluate this for y=2.
So, first step is to plug in 2 for y in the above equation. Therefore,

2=-\frac{4}{3} x+6
2*3=-\frac{4}{3} x*3+6*3 Multiply each sides by common denominator 3
6=-4x+18
6-18= -4x Subtract 18 from each sides.
-12=-4x
-\frac{12}{-4} =-\frac{4x}{-4}
So, x=3

5 0
3 years ago
If f(x) = kx^3+ x^2 − kx + 2, find a number k such that the graph of f contains the point (k, -10)
Elina [12.6K]

If we write k where we see x in the equation and set the result equal to -10, we get the result.

  • f(k)=k(k)^3+k^2-k(k)+2
  • =k^4+k^2-k^2+2
  • =k^4+2=-10
  • k^4=-12
  • k_{1}=\sqrt[4]{3}(-1-i)
  • k_{2}=\sqrt[4]{3}(-1+i)
  • k_{3}=\sqrt[4]{3}(1-i)
  • k_{4}=\sqrt[4]{3}(1+i)

4 0
1 year ago
Matters has 456:8 What s his rate
Olegator [25]

We are given ratio 456:8.

The given ratio can be written in fraction form as \frac{456}{8}

In order to find the rate, we need to divide 456 by 8, because it would give the unit value.

When we divide 456 by 8, we first take multiple of 8 closer to the number 45.

8*6=48 but it's greater than 45, so we would take 8*5 =40.

Subtracting 40 from 45, we get 5.

Getting 6 down, we get 56. Take multiple of 8 upto 56.

8*7= 56.

56 -56=0.

So, on dividing 456 by 8 we got 57.

Therefore, rate is 57 per unit.


3 0
3 years ago
Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle
Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

(x+3)^{2} +(y-4)^{2}=r^{2}

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

r=\sqrt{(2-4)^{2}+(-6+3)^{2}}

r=\sqrt{(-2)^{2}+(-3)^{2}}

r=\sqrt{13}\ units

The equation of the circle is equal to

(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}

(x+3)^{2} +(y-4)^{2}=13

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

(10+3)^{2} +(4-4)^{2}=13

(13)^{2} +(0)^{2}=13

169=13 -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

(x-1)^{2} +(y-3)^{2}=r^{2}

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

r=\sqrt{(6-3)^{2}+(2-1)^{2}}

r=\sqrt{(3)^{2}+(1)^{2}}

r=\sqrt{10}\ units

The equation of the circle is equal to

(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}

(x-1)^{2} +(y-3)^{2}=10

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

(11-1)^{2} +(5-3)^{2}=10

(10)^{2} +(2)^{2}=10

104=10 -----> is not true

therefore

The point is not on the circle

The statement is false

7 0
3 years ago
Which equation can be used to determine the distance between the origin and (-2,-4)?
loris [4]

Answer:

I believe it is the second 1

5 0
3 years ago
Other questions:
  • Find the measure of &lt; 1. <br> m &lt; 1 = degrees
    9·1 answer
  • What is the answer to 7/5 = 10.5/b
    9·1 answer
  • Find the simplified form of (-7.4)^0?<br><br> A.-1<br><br> B.-7.4<br><br> C.0<br><br> D.1
    11·1 answer
  • Im confused on this one !
    7·1 answer
  • Find the distance between the points (-4, 6) and (-1,5).
    8·1 answer
  • If a trapezoid with 9.00-cm and 12.00-cm bases has an area of 68.25 cm2, what is its height to the nearest hundredth?
    14·1 answer
  • List from least to greatest<br> 4.1, 0.25, 0.042, 2.21
    6·2 answers
  • Ive.
    7·1 answer
  • Find x.<br> (4x + 7)°<br> (2r + 5)°
    11·1 answer
  • I need help with this
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!