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3 years ago

What kind of slope is (2,4) & 5,1) positive slope, negative slope, zero slope, or undefined slope

Mathematics

2 answers:

Softa [21]3 years ago

8 0

Answer:

negative

Step-by-step explanation:

4-1 / 2-5 =3/-3 = -1 (negative)

Solnce55 [7]3 years ago

6 0

Positive slope is my best guess for the informations givin

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Tell me 3 mathematical things that you know in relation to geometry

sweet [91]

Answer:

Dilations which reduce or enlarge an object. Translations which move the object from one part on the graph to another. I have also learned about how to construct a perpendicular bisector.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

-x/6 + 6 = 32<br> What is the answer and how do I solve it

masha68 [24]

Answer:

x= -120

Step-by-step explanation:

-x/6+6+6=32

Use -a/b=a/-b= -a/-b to rewrite the fraction.
-x/-6+6+6=32
Add the two 6's then you get 12
-x/-6+12=32
Multiply both sides with the equation by 6
-x+72=192
Move the constant to the right-hand side and change its side
-x=192+72
Subtract the numbers, -x=192-72
-x=120
Change the signs on both sides of the equation
You have your answer it is x= -120

8 0

2 years ago

The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each

Fynjy0 [20]

Answer:

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Step-by-step explanation:

Given equation of ellipsoids,

$u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}$

The vector normal to the given equation of ellipsoid will be given by

$\vec{n}\ =\textrm{gradient of u}$

$=\bigtriangledown u$

$=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})$

$=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}$

$=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}$

Hence, the unit normal vector can be given by,

$\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}$

$=\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}$

$=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Hence, the unit vector normal to each point of the given ellipsoid surface is

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

3 0

3 years ago

Which expression is equivalent to

Tresset [83]

Answer:

j^13

Step-by-step explanation:

j j j j j j j j j j j j j j

There are 13 j's so we raise j to the 13 power

j^13

5 0

2 years ago

Unit rate of 50 meters in 27.5 seconds

ElenaW [278]

50 meters/27.5 seconds = 1.818 meters /sec

3 0

2 years ago

Read 2 more answers