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Kryger [21]
3 years ago
13

— 4x — Зу = = 9 5х = 15 Help me now

Mathematics
1 answer:
blsea [12.9K]3 years ago
8 0

Answer:

y=-7

x=3

Step-by-step explanation:

I just used a calculator. Hope this helps. :)

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Can any one slove this
Rashid [163]
The exterior angle is = to the 2 interior angles.
83 = (9x + 4) + (4x + 1) Remove the brackets
83 = 9x + 4 + 4x + 1 Group the like terms
83 = 9x + 4x + 4 + 1 Add the like terms.
83 = 13x + 5 Subtract 5 from both sides.
78 = 13x Divide by 13
78 / 13 = x
x =  6


So They want the angles
9x + 4 = 9*6 + 4 = 58
4x + 1 = 4*6 + 1 = 25

When you add these two together you should get 83. Do you?
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81, 27, 9 finish the sequence
ololo11 [35]
3, 1, \frac{1}{3}, \frac{1}{9}
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I am struggling hard out with linear algebra in math level one
Elena L [17]
I would recommend "Introduction to Linear Algebra," by Gilbert Strang. It is a compact but very helpful textbook reference written by a well-known MIT professor. There is a corresponding online MIT course that is free, so that's a bonus. I am currently using it to study linear algebra with no class or previous experience, and I think it does a solid job of explaining things. Each section in the book has a set of questions for you to work through, and answers to selected questions appear in an appendix at the end of the book. Hope this helps!
4 0
3 years ago
Which expression is equivalent to the given expression?
jasenka [17]

Answer:

C.) 2(x-3)(x-4)

Step-by-step explanation:

I think so

8 0
2 years ago
Which of the following are solutions to the equation below?
sladkih [1.3K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

Step-by-step explanation:

considering the equation

2x^2\:-\:4x\:-\:3\:=\:x

solving

2x^2\:-\:4x\:-\:3\:=\:x

2x^2-4x-3-x=x-x

2x^2-5x-3=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

solving

x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5+\sqrt{49}}{2\cdot \:2}

x=\frac{5+7}{4}

x=3

also solving

x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}

x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}

x=\frac{5-\sqrt{49}}{4}

x=-\frac{2}{4}

x=-\frac{1}{2}

Therefore,

                 \mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

                  x=3,\:x=-\frac{1}{2}

7 0
3 years ago
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