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kati45 [8]
3 years ago
11

The board of directors of a company knows that the probability that the carbon emission from the company’s manufacturing unit is

exceeding the permissible level is 35%. A consultant is hired to use a carbon footprint calculator to test for the emission level. The accuracy of this test is said to be 85%.
What is the probability that the manufacturing unit has carbon emission beyond the permissible emission level and the test predicts this?
0.2975

0.0525
0.0975
0.5525
0.6325
Mathematics
2 answers:
Fantom [35]3 years ago
6 0
The probability of that the carbon emission is exceeding permissible level in a company is given as 35% and in decimal is 0.35. The calculator test has an accuracy of 85% or 0.85. This can be solved using the probability of two independent events occurring. Let event A be the carbon emission exceeding permissible level and event B be the accuracy of the test. P (A and B) = P(A)xP(B) = 0.35x0.85 = 0.2975
kobusy [5.1K]3 years ago
6 0
I find that:
P (A and B) = P(A)xP(B) = 0.35x0.850
Therefore .2975 or option A
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Classify the following as discrete or continuous random variables.
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Answer:

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While a continuous variable can take any value in the range, like x ∈ {x₁, xₙ}.

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Here the weight depends on the number of apples in the bag, and we can have only whole numbers of apples in the bag, so this is clearly a discrete variable.

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8 0
3 years ago
Why does math get so hard that you have an answer but you forget what your answer was because it was so so so so so so so so so
svetoff [14.1K]
Bc u dont write ur work down. If u actually take the steps to do the question it wont be that bad
8 0
3 years ago
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How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
1 year ago
ANSWER ASAP WILL GIVE BRAINLIEST! 30 POINTS!!
podryga [215]

Answer:

y=|x-1|-1

Step-by-step explanation:

hope that helps :)

4 0
3 years ago
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nydimaria [60]

Answer:

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