This table shows the heights of four boxes that need to be mailed.

Which is the distance from point A to B?

Aleks04 [339]

Answer:

D) radical 26

Step-by-step explanation:

So this is a question where you need to find the hypotenuse of a triangle

the sides are 1 and 5

you can use Pythagoras (a^2+b^2=c^2)

substitute the values in

1^2+5^2=c^2

simplify the exponents

1+25=c^2

add them together

26=c^2

take the square root of 26

the answer is radical 26

5 0

3 years ago

A student has learned that test scores in math are determined by this quadratic function: s(t) = -(t-6)^2 + 99

ser-zykov [4K]

Answer:

a. 6, b. 99, c. 63

Step-by-step explanation:

A) The function s(t) is in the vertex form. The standard vertex form is a(x-h)+k where the vertex is (h,k). The vertex is the highest (or lowest in some cases) point of the graph, so if we use s(t) to get the vertex we get that h=6 and k=99. This means that for a student to get a perfect score they need to study 6 hours

B) We can just take the k value from the first question because that's the highest value for s(t), so the highest score will be 99

C) For this one just plug in 0 for time, so -(0-6)^2+99. This equals -(-6)^2+99, which equals 99-36 =63

4 0

3 years ago

Everyday,Tobys burrito stand uses 3 bags of tortillas, for how many days will2/3 of a bag of tortillas last

Ulleksa [173]

Set up a ratio.
3 bags/1 day = 2/3 bag/x day
Cross multiply to solve.
3x=2/3
So x=2/3(1/3)=2/9 of a day

8 0

3 years ago

Read 2 more answers

2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de

Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let $(x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)$

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

⇒ $d=\sqrt{(2-5)^2+(4-3)^2}$

⇒ $d=\sqrt{9+1}$

⇒ $d=\sqrt{10}$ ....(1)

Now, we find the length of M'K'

let $(x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)$

$d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}$

⇒ $d^{'}=\sqrt{(-2+5)^2+(3-4)^2}$

⇒ $d^{'}=\sqrt{9+1}$

⇒ $d^{'}=\sqrt{10}$ .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct

3 0

4 years ago

Read 2 more answers

What is the area of the figure?

mash [69]

Check the picture below.

$\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh\qquad \qquad A=\cfrac{1}{2}(12\sqrt{2})(12\sqrt{2})\implies A=6\sqrt{2}\cdot 12\sqrt{2} \\\\\\ A=6\cdot 12\sqrt{2}\cdot \sqrt{2}\implies \implies A=72(\sqrt{2})^2\implies A=72\cdot 2\implies A=144$

8 0

3 years ago