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3 years ago

What is an equation for a circle with a center at (-2,3) and a radius of 3

Mathematics

1 answer:

neonofarm [45]3 years ago

3 0

Answer:

(x+2)² + (y–3)² = 3²

Step-by-step explanation:

just use the standard formula

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A pillar is 15 m high the diameter is 84 cm what is the surface area

NARA [144]

Answer:

1416 cm

Step-by-step explanation:

Use calcutor shows everthinh

3 0

2 years ago

The temperature in Miami, Florida is 22 degrees warmer than three times the temperature in Bangor, Maine. The temperature in Mia

balandron [24]

Answer:

See Explanation

Step-by-step explanation:

Let the temperatures of Miami and Bangor be M and B degrees respectively.

According to the given information:

M = 3B + 22... (required equation)

Plug M = 82

82 = 3B + 22

82 - 22 = 3B

60 = 3B

B = 60/3

B = 20 degrees

Thus, the temperature in Bangor is 20 degrees.

3 0

2 years ago

Enter the correct answer in the box. What is the standard form polynomial that represents this product?

JulsSmile [24]

Answer: -8m^5+10m^4+9m^3-16m^2+5m

Step-by-step explanation:

I had this question on a recent test and got it right

Hope this helps! :)

8 0

3 years ago

Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05