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4 years ago

9

The perimeter of the rectangular picture frame is 108 mm. Find its length and width if the width is 3 more than twice the length

.

1 answer:

drek231 [11]4 years ago

7 0

Answer: a=17 mm length

b=37 mm width

Step-by-step explanation:

P=2a+2b

a -length

b-width

b=2a+3

------------------

108mm=2a+2(2a+3)

108=6a+6

6a=102

a=17 mm

b=17*2+3

b=34+3

b=37 mm

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Combine terms/simolify

-Dominant- [34]

Answer:

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Step-by-step explanation:

Since we have common denominators inside the parentheses, we can combine the denominators. Then, we get the following expression:

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$2\huge\text{(}\dfrac{m - 2}{5} \huge\text{)} + \dfrac{3}{5}$

Now, we can multiply the expression inside the parentheses by 2.

$\huge\text{(}\dfrac{2m - 4}{5} \huge\text{)} + \dfrac{3}{5}$

Since the expression inside the parentheses cannot be <u>simplified further</u>, we can open the parentheses and simplify the expression.

$\dfrac{2m - 4}{5} + \dfrac{3}{5}$

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$\dfrac{2m - 4 + 3}{5}$

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Learn more about combining like terms: brainly.com/question/13080103

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2 years ago

Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR

erik [133]

Answer:

392

Step-by-step explanation:

Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.

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Segment XY is the diagonal of the square XAYB, by Pythagorean theorem,

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