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2 years ago

Help help!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

ELEN [110]2 years ago

8 0

Your answer is the bottom right number line.

To answer this question we should first do the calculation 1/8 - (-3/4) to find out what the final answer should be:

To subtract fractions they must have a common denominator, so we’re going to multiply -3/4 by 2 to get -6/8. This will give us:

1/8 - (-6/8) = 1/8 + 6/8 = 7/8. (this turns into + because when you subtract a negative number the minus sign cancels out)

Therefore the correct answer must land on 7/8 on the number line, which is 1 mark away from 1 because each mark represents 1/8, so your answer is the number line in the bottom right.

I hope this helps!

Paladinen [302]2 years ago

3 0

Answer:

bottom right

Step-by-step explanation:

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3 years ago

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According to the order of operations, which of the following operations should be completed first in the following expression?

Kamila [148]

Answer:

Step-by-step explanation:

simplify (5-3)

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3 years ago

Evaluate: 6-(2/3)^2 A. 17/3 B. 52/3 C. 49/9 D. 50/9

Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

....................................................................................................................................

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations! :)

$\dag\textsf{Acronym \: PEMDAS}$

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is $\mathsf{6-(\cfrac{2}{3})^2}$

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain $\mathsf{6-\cfrac{4}{9}}$ .

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: $\mathrm{\cfrac{6}{1}-\cfrac{4}{9}}$ . Now let's multiply the denominator and the numerator of the first fraction times 9: $\mathrm{\cfrac{54}{9}-\cfrac{4}{9}}$ .

See, now the fractions have the same denominator. All we should do now is subtract the numerators: $\mathrm{\cfrac{50}{9}}$ .