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3 years ago

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Given the following points from a quadratic equation, {(-1,1),(0,-2),(1,-3),(2,-2),(3,1)} Find the rate of change between (-1,1)

and (3,1) A 1 B Undefined C -3 D 0

1 answer:

HACTEHA [7]3 years ago

4 0

B undefined it is not constent

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A line with a slope of 6 passes through the points (8,h) and (5,

LenaWriter [7]

$\bf (\stackrel{x_1}{8}~,~\stackrel{y_1}{h})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-8}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-h}{5-8}=6\implies \cfrac{-8-h}{-3}=6 \\\\\\ -8-h=-18\implies -8+18=h\implies 10=h$

7 0

3 years ago

Can someone help with this and explain answer please.

photoshop1234 [79]

Because the triangles are similar the ratio of all the sides would be the same. So you need to find the ratio of the common sides and then use that ratio to find the unkown side.

In this picture sides FG = 52, FV would be the same side and is 24.

Dividing 24/52 = 0.461, so the unkown side WV would be 0.444 of it's common side HG.

HG = 39

39 * 0.461= 18.

The answer is C. 18

3 0

3 years ago

Read 2 more answers

You have 100 dollars in your bank account the first year your account increases 7% the second year it decreases 7% how much mone

Elena-2011 [213]

Answer: Stay the same, 100

Step-by-step explanation: well 7%-7% still equals zero. So it’s not effected, I think.

4 0

3 years ago

Which equation has the solutions x = -3 ± √3i/2 ?

Maurinko [17]

Answer:Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

Note: None of options matches with given question.

instead of "-3" , there should be "- $\frac{3}{2}$ ".

Step-by-step explanation:

Note: None of options matches with given question.

instead of "-3" , there should be " $\frac{3}{2}$ ".

Here, First thing you have to observe the nature of roots.

∴ x = - $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i and x = - $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$

∴ [ x+( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) ][ x+( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + x( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i)+ x( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + $\frac{3}{2}$ x + $\frac{\sqrt{3}}{2}$ ix + $\frac{3}{2}$ x - $\frac{\sqrt{3}}{2}$ ix + (3- $\frac{\sqrt{3}}{2}$ i)(3+ $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{\sqrt{3}}{2}$ i)( $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{3}{4}$ ) $i^{2}$ ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ + ( $\frac{3}{4}$ ) ] =0

∴ [ $x^{2}$ + 3x + $\frac{12}{4}$ ] =0

∴ [ $x^{2}$ + 3x + 3 ] =0

Thus, Answer is option C : <em>[ $x^{2}$ + 3x + 3 ] =0 </em>

6 0

3 years ago

Last month, Grayson and Justine sold candy to raise money for their debate team. Justine sold 1 1/5 times as much candy as Grays

ale4655 [162]

Answer: 4/5 of a box of candy

Step-by-step explanation:

Justine sold 1¹/₅ times the ²/₃ of a box of candy that Grayson sold.

Justin sold;

= 1¹/₅ * ²/₃

= 6/5 * 2/3

= 12/15

= 4/5 of a box of candy

6 0

3 years ago