B. Though soda cans are made from aluminum, aluminum itself is not a renewable resource.
You can recycle aluminum cans but this not a renewable resource.
<span>One parent is an albino with the genotype aa (recessive homozygous), while another parent has genotype AA (dominant homozygous). If they mate:</span>
<span>
Parents aa x AA</span> F1 generation: Aa Aa Aa Aa <span><span>
This means that </span>c. all offspring are normal.</span>
<span>All of them are carriers of the albino allele (a), but albinism is expressed only when there are two recessive alleles.</span>
Answer:
3/16
Explanation:
This question involves two different genes coding for earlobe shape and earwax quality. The alleles for attached earlobes (A) and wet earwax (E) are dominant over the alleles for free earlobes (a) and dry earwax (e).
According to this question, two humans mate who are heterozygous for both genes i.e. AaEe × AeEe. Each parent will produce the following gametes: AE, Ae, aE, ae.
Using these gametes in a punnet square (see attached image), the following proportion of offsprings will be produced:
* Attached earlobe, wet earwax (A_E_) = 9/16
* Attached earlobe, dry earwax (A_ee) = 3/16
* Free earlobe, wet earwax (aaE_) = 3/16
* Free earlobe, dry earwax (aaee) = 1/16
Hence, the probability of these parents having their first child with dry earwax (ee) and attached earlobes (A_) i.e. genotype A_ee is 3/16.
Here is the answer but not complete i forgot the ribosome diagram
But I hope it helps