Answer:
i dont get the question
Step-by-step explanation:
Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
Answer:
Translated how?
Step-by-step explanation:
Answer:
Third inequality has dashed boundary.
Step-by-step explanation:
An equality has dashed boundary on graphing when it strictly less than or strictly greater than Symbolically ( < or > sign in the inequality)
boundary line is is solid line when the inequality is with symbol of equality also ( < = or > = )
Here we can see that all the inequalities except third one has symbol less than or equal to or greater than or equal to . And third inequality is with
symbol > (greater than ) that mean strictly less than ,therefore on graphing
third inequality gives dashed line boundary.