Ask question

Ask question

All categories

3 years ago

9

Louis surveyed 50 people at a track meet to find out what their favorite events were. He found that 5 people like shot-put the b

est. What percent of his pie chart would this represent?

2 answers:

julia-pushkina [17]3 years ago

7 0

Answer:

10%, or 36°.

Step-by-step explanation:

5 out of 50 people is 5/50 = 0.1, which is 10%.

10% of 360 = 0.1(360) = 36

Georgia [21]3 years ago

3 0

This equals to 10% of the surveyed people which are 50 people

You might be interested in

Answer please i need

frosja888 [35]

Answer:

I'm pretty sure its C

Step-by-step explanation:

shhshshdhdhdjsjdncgc sg shhshshdhdhdjsjdncgc ghh Judy ch

5 0

3 years ago

Consider the figure below.<br><br><br><br> Find the value of x.

Flauer [41]

Answer:

x = 5

Step-by-step explanation:

When two straight lines intersect, four angles are formed. The angles that are directly opposite of each other are equal. Since the angles are equal set the values equal to each other and solve for x.

5x - 5 = 2x + 10

5x - 5 - 2x = 2x + 10 - 2x

3x - 5 = 10

3x - 5 + 5 = 10 + 5

3x = 15

3x/3 = 15/3

x = 5

6 0

3 years ago

Element X decays radioactively with a half life of 11 minutes. If there are 870 grams of Element X, how long, to the nearest ten

serg [7]

Answer:

It would take 27.5 minutes the element to decay to 154 grams.

Step-by-step explanation:

The decay equation:

$\frac {dN}{dt}\propto -N$

$\Rightarrow \R\frac {dN}{dt}=-\lambda N$

$\Rightarrow \frac {dN}N=-\lambda dt$

Integrating both sides

$\Rightarrow \int \frac {dN}N=\int-\lambda dt$

$\Rightarrow ln|N|=-\lambda t+c$

When t=0, N= $N_0$ = initial amount

$ln|N_0|=-\lambda .0+c$

$\Rightarrow c=ln|N_0|$

$ln|N|=-\lambda t+ln|N_0|$

$\Rightarrow ln|N|-ln|N_0|=-\lambda t$

$\Rightarrow ln|\frac{N}{N_0}|=-\lambda t$

Decay equation:

$ln|\frac{N}{N_0}|=-\lambda t$

Given that, the half life of of element X is 11 minutes.

For half life, $N=\frac12 N_0$ , t= 11 min.

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{\frac12N_0}{N_0}|=-\lambda . 11$

$\Rightarrow ln|\frac12}|=-\lambda . 11$

$\Rightarrow -\lambda . 11=ln|\frac12}|$

$\Rightarrow \lambda =\frac{ln|\frac12|}{-11}$

$\Rightarrow \lambda =\frac{ln|2|}{11}$ [ $ln|\frac12|=ln|1|-ln|2|=-ln|2|$ , since ln|1|=0]

N=154 grams, $N_0$ = 870 grams, t=?

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{154}{870}|=-\frac{ln|2|}{11}.t$

$\Rightarrow t= \frac{ln|\frac{154}{870}|\times 11}{-ln|2|}$

=27.5 minutes

It would take 27.5 minutes the element to decay to 154 grams.

5 0

3 years ago

Use all of the angle relationships that we have covered to find the missing angles in the puzzle below

Sophie [7]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

I started with triangle GHJ on the right. It is isosceles, so ...

g = 48°

h = 2(90 -g) = 84°

k = 180° -h = 96°

Then, on the lower right, we have ...

a = 180° -143° = 37°

b = 143°

c = e = a = 37°

f = 90° -e = 53°

At vertex D, we also have ...

85° +d = b ⇒ d = 143° -85° = 58°

In triangle DGH, we have ...

m + d = h ⇒ m = h -d = 84° -58° = 26°

The sum of angles in triangle DGP is 180°, so ...

p = 180° -85° -26° = 69°

Finally, ...

s = p = 69°

r = 180° -p = 111°

_____

The relationships we used are ...

corresponding angles are congruent (at a transversal of parallel lines)
alternate interior angles are congruent
an exterior angle equals the sum of remote interior angles
acute angles in a right triangle are complementary
angles in a triangle sum to 180°
linear pair angles are supplementary
angle sum theorem

7 0

3 years ago

Read 2 more answers

PLEASE HELP I NEED ANSWER NOW

Amiraneli [1.4K]

7-(-2)=7+2 :)))) happy holidays!

7 0

3 years ago