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mariarad [96]
3 years ago
8

Given: ∠WXY and ∠YXZ are supplementary angles and ​ m∠WXY=75° ​ Prove: m∠YXZ=105°

Mathematics
2 answers:
mestny [16]3 years ago
6 0

Answer:

m∠WXY + m∠YXZ = 180°

Replacing with the real values:

75° + m∠YXZ = 180°

m∠YXZ = 180° - 75°

<u>m∠YXZ = 105°</u>

Step-by-step explanation:

1. Let's review all the information provided to us to answer the question correctly:

∠WXY and ∠YXZ are supplementary angles

m∠WXY=75°

2. Prove : m∠YXZ=105°

Let's recall that supplementary angles are those angles whose sum is 180 degrees. Therefore,

m∠WXY + m∠YXZ = 180°

Replacing with the real values:

75° + m∠YXZ = 180°

m∠YXZ = 180° - 75°

<u>m∠YXZ = 105°</u>

Alex17521 [72]3 years ago
5 0

Answer:

Drag an answer to each box to complete this paragraph proof.

Given: ∠WXY

and ∠YXZ are supplementary angles and ​m∠WXY=75°

Prove:m∠YXZ=105°

took the test below is the right answers

Step-by-step explanation:

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(6v^3+42v)/(2v^2+26v+84)
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Answer:
_______________________________________________
The simplied version is:
_______________________________________________
                " \frac{3v(v^2+7)}{(v^2+13v+42)}  "  ;

or; write as:  " \frac{3v(v^2+7)}{(v+7)(v+6)}  " .
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Explanation:
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Given:
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     " \frac{6v^3 +42 v}{2v^2 +26v + 84}  " ;
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     →  Factor out a "6v"\frac{6v(v^2+7)}{2(v^2+13v+42)} in the "numerator"; & factor out a "2" in the denominator;  as follows:
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→ \frac{6v(v^2+7)}{2(v^2+13v+42)} ;
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