Dimension of one of the floors of one room that David wants to install tiles is 18feet long by 12 feet wide
Then
Area of the above room = 18 * 12 square feet
= 216 square feet
Dimension of the floor of the other room that David wants to install tiles is 24 feet long and 16 feet wide
Then
Area of the other room = 24 * 16 square feet
= 384 square feet
Then
The total square feet of the
rooms that David wants to install tiles = 216 + 384
= 600 square feet
Cost of the tile that covers 1 square feet = $5
Cost of the 4 tiles that cover 4 square feet = $17
Then
Area that can be covered with 4 square feet of tiles = 600/4 square feet
= 150 square feet
Minimum cost of covering
the two rooms that David wants to install tiles = 150 * 17 dollars
= 2550 dollars
So the minimum cost of installing the tiles on the two floors of David's two rooms is $2550. I hope the procedure is simple enough for you to understand.
Answer:
ok so you see the equation at the top... you are going to "plug in" the number in the "in" row to get the "out number
Step-by-step explanation:
example
in: 4
-2(-4)+1
8+1
9
so for the out row under -4 you would put 9
-2(-3)+1
6+1
7
so for the out row under 3 you would put 7
Answer:
The length of the circular arc is 8.64 inches
Step-by-step explanation:
Length of circular arc (L) = central angle/360° × 2πr
central angle = pie/4 = 45°, r (radius) = 11 inches
L = 45°/360° × 2 × 3.142 × 11 = 8.64 inches (to two decimal places)
Answer: E: 100%
Step-by-step explanation:
If the class average is currently 70% and she wants to increase it by 10% every week for 3 weeks, 10×3=30% and 70+30= 100%.
PS- It would mean the world to me if you could mark me brainliest!
I am not a professional, I am simply using prior knowledge!