Answer:
The answer is symmetrical
Step-by-step explanation:
x
x x x
x x x x x
x x x x x x x
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1 2 3 4 5 6 7
9514 1404 393
Answer:
A. Simon's unit rate is 2 more miles per hour than Eric's unit rate
Step-by-step explanation:
We are concerned with the number of miles each runs in 1 hour.
For Eric, that means x=1 in his equation, so his mileage is ...
y = 6×1 = 6 . . . . miles
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For Simon, it means we want to find time = 1 hour on the horizontal axis at the bottom of the graph. Then we want to see where the graphed line crosses that vertical line. The point of crossing has horizontal line that goes over to 8 on the vertical distance axis. That is, Simon runs 8 miles in 1 hour.
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Eric's unit rate (miles in 1 hour) is 6 miles per hour.
Simon's unit rate (miles in 1 hour) is 8 miles per hour.
Simon's unit rate is 2 more miles per hour than Eric's unit rate.
Answer:
64.5°
Step-by-step explanation:
it is the answer got it nd comment me
Answer:
a. answer to a can be found in the attached file
b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=
0.24+0.06+0.05 = 0.35
c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07
Step-by-step explanation:
"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that gives a 0.8 chance of seed survival, a medium-quality soil that gives a 0.3 chance of survival, and a low-quality soil that gives only a 0.1 chance of survival. These three soil types (high, medium, and low) are present in the habitat in proportions of 30:20:50, respectively. The probability that a seed lands on a particular soil type is proportional to the frequency of that type in the habitat. a. Draw a probability tree to determine the probabilities of survival under all possible circumstances. b. What is the probability of survival of the seed, assuming that it lands"c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
a. Find the probability tree as attached below
b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=
0.24+0.06+0.05 = 0.35
c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07
I’m pretty sure that the answer is the 3rd one
