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Leya [2.2K]
3 years ago
8

Babies born in the United States must have a Social Security card issued before their third birthday. How many different cards c

ould be issued using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9, if each card needs a nine-digit number and the digits can only be used once per card?
Mathematics
2 answers:
melomori [17]3 years ago
8 0
It's a Permutation of 9 digits chosen out of 10 digits with no repeat:

¹⁰P₉ = (10!)/(10-9)! = 3,628,800 cards

svlad2 [7]3 years ago
7 0
10*9*8*7*6*5*4*3*2*1

Considering that when you use a digit you can't use it again, the possibilities of a number filling a specific position is one less than before because the number was already used.

Using this the answer should be
3,628,800
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Answer:

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slamgirl [31]
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4 years ago
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Alchen [17]
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5 and 24/10 = 74/10

Now, divide 74/10 by 4:

74/10 ÷ 4 = 74/10 × 1/4
                
= 74/40
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(Remember that dividing requires you to reciprocate 4)

Hope this helps!


5 0
3 years ago
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IgorLugansk [536]

Answer:

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Step-by-step explanation:

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Answer:

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