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elixir [45]
3 years ago
15

Can someone please help me with this math probability question I would really it. I will give brainliest and like always a thank

s

Mathematics
1 answer:
Margaret [11]3 years ago
6 0

Answer:

1/18 or 5.55...% 2nd question: 10,000

Step-by-step explanation:

She has a one in 6 odds for the dices, and every one for those odds she also has 1 in 3 for the spinner, so you just multiply them.

2nd question: you have to do this differently. This one you need to multiply 10 by 10 by 10 by ten, because for each there are 10 1,2,3,4,5,6,7,8,9,0, so there can be ten in each, so you get 10,000

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Write the recursive formula of 13, 9, 5...
lukranit [14]

Step-by-step explanation:

a(n) = a +(n-1)d

a=13

d=9-13=5-9=-4

°.° a(n) = 13 +(n–1)-4

hope this helps

7 0
3 years ago
A basketball player scored 288 points in 9 games. Use the unit rate to find how many points the player would score in 5 games.
AysviL [449]

Answer:

160 Points in 5 Games

Step-by-step explanation:

The given information will be used as the first ratio. 288 points / 9 games. To find out how many points this player would score in 5 games, we use another ratio with the unknown value, x. This would be x points / 5 games. Put the ratios equal to each other and cross multiply. You will get a final answer of 160.

3 0
3 years ago
EXAMPLE 5 If f(x, y, z) = x sin(yz), (a) find the gradient of f and (b) find the directional derivative of f at (1, 2, 0) in the
solong [7]

Answer:

<h2>a) f =  sin(yz)i + xzcos(yz)j + xycos(yz)k</h2><h2>b) -2</h2>

Step-by-step explanation:

Given f(x, y, z) = x sin(yz), the formula for calculating the gradient of the function is expressed as ∇f(x, y, z) = fx(x, y, z)i+ fy(x, y, z)j+fz(x, y, z)k where;

fx, fy and fz are the differential of the functions with respect to x, y and z respectively.

a) ∇f(x, y, z) = sin(yz)i + xzcos(yz)j + xycos(yz)k

The gradient of f =  sin(yz)i + xzcos(yz)j + xycos(yz)k

b) Directional derivative of f at (1,2,0) in the direction of v = i + 4j − k is expressed as ∇f(1, 2, 0)*v

∇f(1, 2, 0) = sin(2(0))i +1*0cos(2*0)j + 1*2cos(2*0)k

∇f(1, 2, 0) = sin0i +0cos(0)j + 2cos(0)k

∇f(1, 2, 0) = 0i +0j + 2k

Given v = i + 4j − k

∇f(1, 2, 0)*v (note that this is the dot product of the two vectors)

∇f(1, 2, 0)*v =  (0i +0j + 2k)*(i + 4j − k )

Given i.i = j.j = k.k =1 and i.j=j.i=j.k=k.j=i.k = 0

∇f(1, 2, 0)*v = 0(i.i)+4*0(j.j)+2(-1)k.k

∇f(1, 2, 0)*v = 0(1)+0(1)-2(1)

∇f(1, 2, 0)*v =0+0-2

∇f(1, 2, 0)*v= -2

 

Hence, the directional derivative of f at (1, 2, 0) in the direction of v = i + 4j − k is -2

7 0
3 years ago
A boarding kennel mixes dry dog ​
7nadin3 [17]
A) Yes. There is 3x as much dry dog food as there is wet dog food. 1.5 x 3 = 4.5 oz. 2 x 3= 6 oz. 3 x 3 = 9 oz
b) 16.5. (5.5 x 3 = 16.5)
7 0
3 years ago
EXPAND AND SIMPLIFY<br>​
Anit [1.1K]

Answer:

5⁴a²

Step-by-step explanation:

(5³a³)÷5a-¹×5-²a²

5³a³÷5a-¹×5-²a²

5³a³÷5¹-²×a-¹+²

5³a³÷5-¹a

5³a³/5-¹a

5³-(-¹)a³-¹

5⁴a²

5 0
2 years ago
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