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4vir4ik [10]
3 years ago
12

What is the value of this equation

Mathematics
1 answer:
pickupchik [31]3 years ago
8 0

Answer:

Step-by-step explanation:

Alright, lets get started.

The given equation is :

e^{3x+6} =8

taking log on both side

lne^{3x+6}=ln8

(3x+6)lne=ln8

Plugging the value of ln e as 1

3x+6=ln8

Subtracting 6 in both sides

3x+6-6=ln8-6

3x=ln8-6

Dividing 3 in both sides

x=\frac{ln8-6}{3}    ........................  Answer

Hope it will help :)

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Step-by-step explanation:

Final result :

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Reformatting the input :

Changes made to your input should not affect the solution:

(1): "k2"   was replaced by   "k^2".

Step by step solution :

Step  1  :

Trying to factor by splitting the middle term

1.1     Factoring  k2+k-42

The first term is,  k2  its coefficient is  1 .

The middle term is,  +k  its coefficient is  1 .

The last term, "the constant", is  -42

Step-1 : Multiply the coefficient of the first term by the constant   1 • -42 = -42

Step-2 : Find two factors of  -42  whose sum equals the coefficient of the middle term, which is   1 .

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     -14    +    3    =    -11

     -7    +    6    =    -1

     -6    +    7    =    1    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -6  and  7

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Step-4 : Add up the first 2 terms, pulling out like factors :

                   k • (k-6)

             Add up the last 2 terms, pulling out common factors :

                   7 • (k-6)

Step-5 : Add up the four terms of step 4 :

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            Which is the desired factorization

Final result :

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