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2 years ago

Find the area of the shaded region

Mathematics

2 answers:

Tresset [83]2 years ago

5 0

29.5cm , have a good day!

zepelin [54]2 years ago

3 0

Answer:

area of a circle πr^2

r = 10/2 r = 5

π5^2 = 78.5

area of the square length X width

7 x 7 = 49

78.5 - 49 = 29.5

shaded region = 29.5 square cm

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(7,-4);

olga_2 [115]

Literally just plug it in

6(7) + 5(-4) - 42 = 0

42 -20 -42 = 0

-20 = 0

Not a solution.

8 0

2 years ago

What is the equation of this line? A: y=-3/2x B: y=2/3x C: y=-2/3x D: y=3/2x

creativ13 [48]

Answer:

b) y = 2/3x

Step-by-step explanation:

Slope (m) formula: $\frac{y_2-y_1}{x_2-x_1}$

I will be using (3,2) and (-3,-2) to find the slope:

$m=\frac{-2-2}{-3-3}\\m=\frac{-4}{-6} \\m = \frac{2}{3}$

$y = mx + b\\y = \frac{2}{3}x+b$

(3,2)

$y = \frac{2}{3}x+b\\\\2 = \frac{2}{3}(3)+b\\\\2 = 2+b\\-2 -2\\\\0=b$

$y=mx+b\\\\y = \frac{2}{3}x+0\\\\y = \frac{2}{3}x$

Hope this helps!

8 0

2 years ago

Find the area shaded in yellow please!

worty [1.4K]

A= 1/2(7 + 11)(5)
A = 1/2(18)(5)
A = 45 square units

7 0

2 years ago

Read 2 more answers

The perimeter of a square is 40 cm what is its length

lawyer [7]

Answer:

Step-by-step explanation: perimeter = side * 4

therefore the answer is 40 *4

160

7 0

2 years ago

Read 2 more answers

A scientist claims that 7% 7 % of viruses are airborne. If the scientist is accurate, what is the probability that the proportio

Reptile [31]

Answer:

The probability is $P(|p-\^{p}| > 0.03) = 0.0040$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.07$

The mean of the sampling distribution is $\mu_p = 0.07$

The sample size is n = 600

Generally the standard deviation is mathematically represented as

$\sigma_p = \sqrt{\frac{p (1 -p)}{n} }$

=> $\sigma_p = \sqrt{\frac{0.07(1 -0.07)}{600} }$

=> $\sigma_p = 0.010416$

Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

$P(|p-\^{p}| > 0.03) = 1 - P(|p -\^{p}| \le 0.03)$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-0.03 \le p -\^{p} \le 0.03 )$

Now add p to both side of the inequality

=> $P(|p-\^{p}| > 0.03) = 1 - P( 0.07-0.03 \le \^{p} \le 0.03+ 0.07 )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(0.04 \le \^{p} \le 0.10 )$

Now converting the probabilities to their respective standardized score

=> $P(|p-\^{p}| > 0.03) = 1 - P(\frac{0.04 - 0.07}{0.010416} \le Z \le \frac{0.10 -0.07}{0.010416} )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-2.88 \le Z \le 2.88 )$

=> $P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]$

From the z-table

$P(Z \le 2.88) = 0.9980$

and

$P(Z \le -2.88) = 0.0020$

$P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]$

=> $P(|p-\^{p}| > 0.03) = 0.0040$

7 0

3 years ago