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3 years ago

A study at a major university concluded that many students are cheating

Mathematics

2 answers:

Klio2033 [76]3 years ago

7 0

Alright, let's think of the problem like this:

pogonyaev3 years ago

3 0

Right Answer: 1500

We know that 675 of the students surveyed said they cheated in 1 to 7 courses, and this represents 45% of the total students that participated in the survey, as shown in the graph.

If we want to know the total students surveyed (100%) we can use the Rule of Three as follows:

if 45% represents -----675 students

100% represents--------X students

45% -----675 students

100% --------X students

And this is solved in the following way:

$X=\frac{(100\%)(675)}{45\%}$

Finally:

X=1500>>>>>This is the total amount of students surveyed or the 100%

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George Box, a famous statistician, once said, "All models are wrong, but some are useful.” What did George Box mean by this stat

Katena32 [7]

Basically meaning that no model can exactly be on point with whatever it is modeling. Two things cannot be EXACTLY identical to what they are referring to, but it is saying that some can get close enough to be useful as an example.

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3 years ago

Read 2 more answers

The operations manager at a compact fluorescent light bulb (CFL) factory needs to estimate the mean life of a large shipment of

aliya0001 [1]

Answer:

The 95% confidence interval estimate for the population mean life of compact fluorescent light bulbs in this shipment is between 7,255 hours and 7,745 hours.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.95$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{1000}{\sqrt{64}} = 245$

The lower end of the interval is the sample mean subtracted by M. So it is 7500 - 245 = 7255 hours.

The upper end of the interval is the sample mean added to M. So it is 7500 + 245 = 7745 hours.

The 95% confidence interval estimate for the population mean life of compact fluorescent light bulbs in this shipment is between 7,255 hours and 7,745 hours.

7 0

3 years ago

Problem 2.191 A researcher receives 93 containers of oxygen. Of those containers, 20 have oxygen that is not ionized and the res

Ahat [919]

Answer:

Step-by-step explanation:

Given that there are 20 non ionized containers and 73 ionized containers

Two samples are drawn without replacement

a) the probability that the first one selected is not ionized= $\frac{20}{93} =0.215$