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anyanavicka [17]
3 years ago
11

George Box, a famous statistician, once said, "All models are wrong, but some are useful.” What did George Box mean by this stat

ement?
Mathematics
2 answers:
Bogdan [553]3 years ago
7 0

Answer: Sample answer : a model is an estimate or approximation of a data set. In the real world, there are too many variables to know exactly what will happen. However, if a model is a good fit, then it can be used to make predictions about what will happen. With a useful model, a predicted value should be a good estimate of an observed value.

Katena32 [7]3 years ago
3 0
Basically meaning that no model can exactly be on point with whatever it is modeling. Two things cannot be EXACTLY identical to what they are referring to, but it is saying that some can get close enough to be useful as an example. 

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Formula to find base of a triangle
ohaa [14]

Answer:

b=2 A/a sin γ

Step-by-step explanation:

8 0
3 years ago
Twice Use what you have learned to compare circles by their characteristics. 1. Draw each circle. A. Radius length of 3 centimet
Gwar [14]

Answer:

1. a. Please find attached, the diagram for the first circle with radius = 3 cm

b. Please find attached, the diagram for the second circle with diameter = 3 cm

2. The similarities are;

a) Both circles can be described by a point and a radius or a diameter

The differences are;

a) The length of the radiuses are different for the two circles (3 cm and 1.5 cm)

b) The circumferences of the two circles are different

c) The area covered by the two circles are different

3. The circumference of the circle with radius equal to 3 cm is larger than the circumference of the circle with diameter equal to 3 cm

4. The circumference to diameter ratio of the circle with radius  = 3 cm is π

The circumference to diameter ratio of the circle with diameter  = 3 cm is π

Both circles have equal circumference to diameter ratio given that the circumference = π × The diameter

Step-by-step explanation:

1. a. The radius length of the first circle = 3 cm

The diagram for the first circle with radius 3 cm is attached

b. The diameter length of the second circle = 3 cm

The diagram for the second circle with diameter 3 cm is attached

2. The similarities are;

a) Both circles can be described by a point and a radius or a diameter

The differences are;

a) The length of the radiuses are different for the two circles (3 cm and 1.5 cm)

b) The circumferences of the two circles are different

c) The area covered by the two circles are different

3. The circumference of the circle with radius equal to 3 cm is 2 × π × 3 = 6·π cm

The circumference of the circle with diameter equal to 3 cm is π × 3 = 3·π cm

Therefore, the circumference of the circle with radius equal to 3 cm is larger than the circumference of the circle with diameter equal to 3 cm

4. The circumference to diameter ratio of the circle with radius = 3 cm is 6·π cm/(2 × 3 cm) = π

The circumference to diameter ratio of the circle with diameter = 3 cm is 3·π cm/(3 cm) = π.

Both circles have equal circumference to diameter ratio given that the circumference = π × The diameter.

7 0
3 years ago
The geometric mean of 4 and 9 is _____. <br> A.) 36<br> B.) 6<br> C.) 18<br> D.) 6.5
Snezhnost [94]
Hey there,

The geometric mean of 4 and 9 is \boxed{6}

Reason: The square root of the product of the both numbers.

The geometric mean<span> of </span>4 and 9<span> is 6. </span>4<span> * </span>9<span>. = 6
</span>
~Jurgen
7 0
3 years ago
Read 2 more answers
What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?
ZanzabumX [31]

Answer:

x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: x=\frac{-b+\sqrt{b^2-4ac} }{2a} or x=\frac{-b-\sqrt{b^2-4ac} }{2a}.

Here, a = 6, b = -24, and c = 1. Plug these in:

x=\frac{-b+\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}

AND

x=\frac{-b-\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}

Thus, the zeroes are: x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}.

3 0
3 years ago
Read 2 more answers
What is 100x398+56.
Serjik [45]

Answer:

39856

Step-by-step explanation:

100 × 398 + 56

39800 + 56

39856

8 0
3 years ago
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