Answer:
8
Step-by-step explanation:
6(6)-20-32(1/4)
36-20-8
16-8
8
Let the shorter leg = a.
The longer leg, b = a + 4.
The hypotenuse, c = a + 8
a^2 + b^2 = c^2
a^2 + (a + 4)^2 = (a + 8)^2
a^2 + a^2 + 8a + 16 = a^2 + 16a + 64
a^2 - 8a - 48 = 0
(a - 12)(a + 4) = 0
a - 12 = 0 or a + 4 = 0
a = 12 or a = -4
a = -4 is discarded because it is negative.
a = 12
b = 16
c = 20
The lengths are 12 m, 16 m, and 20 m.
Answer:
Less than 13 pounds of grapes,
as 14 pounds of grape exceeds $35.80,
If you order as low as zero pounds of grapes, then the price of apple pounds would be $35.80/20 =$1.79 per pound
Step-by-step explanation:
Let
Quantity of Apple and grapes=20
Cost of apple=$2.19
Cost of grape=$2.60
Total cost of apple and grape=$35.80
a+g=20
a=20-g
PaQa+PgQg=35.80
2.19(20-g)+2.60g=35.80
43.8-2.19g+2.60g=35.80
0.41g=35.80-43.8
0.41g=-8
g=-8/0.41
g= -19.51
PaQa+PgQg=35.80
2.19a+2.60(-19.51)=35.80
2.19a-50.726=35.80
2.19a=35.80+50.726
2.19a=86.526
a=86.526/2.19
=39.51
PaA+PgG=35.80
Pa(20-G)+2.60G=35.80
35.80/2.60 = 13.77 pounds of grapes, but no money will be left to buy apples, unless Pa=0
G<13.77
If I pick 10, then 2(10)+13=33
If I pick 15, then 2(15)+13=43
If I pick 12, then 2(12)+13=37
