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3 years ago

Solve v^3 = -26 where v is a real number. Simplify your answer as much as possible.

Mathematics

1 answer:

il63 [147K]3 years ago

5 0

Answer:

nearby -3

Step-by-step explanation:

When v^3 is -26, your v is equal to $-\sqrt[3]{26}$ .

3^3 is 27, so v is nearby 3.

or, It would be nearby 3.9

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Answer:

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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3 years ago

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svet-max [94.6K]

Answer:

Hi, There!

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Step-by-step explanation:

$\frac{3}{4} ~x~\frac{2}{3} = \frac{3 ~x~2}{4~x~3}$

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Take Care!

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5 0

3 years ago

1) A ball is dropped from a height of 50 feet. How long after it is dropped will it reach a height of 18 feet?

Nookie1986 [14]

Answer: 1.41 seconds

Step-by-step explanation:

The problem gives the initial velocity by saying "dropped." This indicates a velocity of zero. Acceleration can also be found because the object is in free fall. It would experience the acceleration of gravity. We can use the kinematic equation:

$(y_f-y_i)=V_it+\frac{1}{2}at^2$

The velocity term completely cancels because the object was dropped with an initial velocity of 0.

$(18-50)=\frac{1}{2} (32.17)t^2\\$

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8 0

3 years ago