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3 years ago

7

3x + 5y = 30

1 answer:

GrogVix [38]3 years ago

3 0

Answer:

$y= - \frac{3x}{5} + 6$

Step-by-step explanation:

The given linear equation is

$3x + 5y = 30$

To solve for y, we first subtract 3x from both sides to obtain:

$5y = 30 - 3x$

Divide through by 5

$\frac{5y}{5} = \frac{30}{5} - \frac{3x}{5}$

This simplifies to

$y= 6- \frac{3x}{5}$

Or

$y= - \frac{3x}{5} + 6$

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Solve using the quadratic formula<br><br> x^2-4x+1=0

sergiy2304 [10]

Answer:

x=2+ or - the square root of 3

Step-by-step explanation:

solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.

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3 years ago

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Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

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3 years ago

Which of these numbers is between

serious [3.7K]

I think the answer is D. $11/6$

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3 years ago

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Find the median. 90, 88, 100, 82, 80.

gavmur [86]

Answer:

100 is the median for te above observations

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3 years ago

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Mark said he can decompose five six into three fractions with three different numerators and the same denominator is this possib

Kazeer [188]

Answer:

1/6 ; 2/6 ; 2/6

Step-by-step explanation:

To split 5/6 into. 3 different fractions with the same denominator and different numerator values;

The integer value of the numerator 5 can be divided into 3 different whole Number values ;

It could be :

5 = 3 + 1 + 1

5 = 2 + 2 + 1

Hence, we could have ;

3/6 +. 1/6 + 1/6

Or

2/6 + 2/6 + 1/3

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3 years ago