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UNO [17]
3 years ago
11

A cereal box says that now it contains 20% more. Originally, it came with 20 ounces of cereal. How much cereal does the box come

with now?
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
6 0

Answer:24ounces

Step-by-step explanation:

Multiply 20 ounces by .20 (The percent) then add your answer to the 20 ounces.

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In the eighth grade,322 students voted for the new mascot to be a tiger.this was 7/10 of the total number of students in the eig
kolbaska11 [484]
322 is 7/10 of all the students.

322 / 7 = 46

46 is 1/10 of all the students.

46 × 10 = 460

460 is 10/10 of all the students

There are 460 students in eighth grade.
8 0
3 years ago
Read 2 more answers
A total of $76,000 is to be​ invested, some in bonds and some in certificates of deposit​ (CDs). If the amount invested in bonds
Anestetic [448]

Answer:

The amount invested as certificates of deposit is $ 35,000 and The amount invested as bonds is  $ 41,000

Step-by-step explanation:

Given as :

The total amount to be invested as bonds and certificates of deposit (CD) = $76,000

Let the amount invested as bonds = $ x + $6000

And The amount invested as CD = $ x

Now, According to question

The amount invested as CD + The amount invested as bonds = $ x  + $ x + $6000

Or, $ x  + $ x + $6000 = $76,000

Or, $ 2x = $76,000 - $6000

So,  $ 2x = $70,000

∴  x = \frac{70000}{2} = $ 35,000

And $ x + $6000 = $ 35,000 + $6000 = $ 41,000

Hence The amount invested as certificates of deposit is $ 35,000 and The amount invested as bonds is  $ 41,000    Answer

4 0
3 years ago
Simplify: 2a-2/3b-4 1/2a- 1/6b
Tasya [4]

Answer:

-5(3a+b)

   6

Step-by-step explanation:

-5(3a+b) over 6

7 0
3 years ago
In a sample of 230 teenagers, 202 would like to have smaller class sizes at their school. Find the sample
marishachu [46]

Answer:

The sample proportion is 0.88.

The margin of error is of 0.04.

The interval likely to contain the true population proportion is (0.84,0.92).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Margin of error:

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

Sample of 230 teenagers, 202 would like to have smaller class sizes at their school.

This means that n = 230, and that the sample proportion is:

\pi = \frac{202}{230} = 0.88

The sample proportion is 0.88.

Standard 95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Margin of error:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.96\sqrt{\frac{0.88*0.12}{230}}

M = 0.04

The margin of error is of 0.04.

Confidence interval:

Sample proportion plus/minus margin of error. So

0.88 - 0.04 = 0.84

0.88 + 0.04 = 0.92

The interval likely to contain the true population proportion is (0.84,0.92).

5 0
3 years ago
‼️help please ASAP ‼️
Lana71 [14]
The answer to this question is true. The equation (x-h)^2+(y-k)^2 = r^2 represents a circle with a center at (h,k). Taking (h,k) = (-2,2) and r = 3 results in (x+2)^2 + (y-2)^2 = 9. A negative subtracted by a negative is a positive.
3 0
3 years ago
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