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san4es73 [151]
4 years ago
5

A mile is 5,280 feet between which two integers is the elevation of the trench in miles-21,844 feet is between and miles

Mathematics
2 answers:
Bumek [7]4 years ago
4 0

Answer:

21,844 feet is between 4 and 5 miles.

Step-by-step explanation:

We are asked to find two integers between which the elevation of the 21,844 feet trench lies in miles.

Let us convert 21,844 feet into miles by dividing 21,844 by 5,280 as 1 mile equals 5,280 feet.

\frac{21,844}{5,280}=4.137

We can see that 21,844 feet is equal to 4.137 miles, which is greater than 4 miles and less than 5 miles, therefore, 21,844 feet is between 4 and 5 miles.

faust18 [17]4 years ago
3 0

the answer is 16,564

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Simplify the expression. -8n - 2n​
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Answer:

-10n

Step-by-step explanation:

To simplify, you add like terms so by looking at the problem you can see the 8 and the 2 both have an n after, so you can combine them.

so negative 8 minus 2 = -10 and since there are like terms you add the n making the answer -10n

If it was -8n -2 you could not simplify it since the 2 is single and without the same letter

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3 years ago
A distribution of values is normal with a mean of 60 and a standard deviation of 16. From this distribution, you are drawing sam
professor190 [17]

Answer:

The interval containing the middle-most 76% of sample means is between 56.24 and 63.76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

A distribution of values is normal with a mean of 60 and a standard deviation of 16.

This means that \mu = 60, \sigma = 16

Samples of size 25:

This means that n = 25, s = \frac{16}{\sqrt{25}} = 3.2

Find the interval containing the middle-most 76% of sample means.

Between the 50 - (76/2) = 12th percentile and the 50 + (76/2) = 88th percentile.

12th percentile:

X when Z has a p-value of 0.12, so X when Z = -1.175.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-1.175 = \frac{X - 60}{3.2}

X - 60 = -1.175*3.2

X = 56.24

88th percentile:

Z = \frac{X - \mu}{s}

1.175 = \frac{X - 60}{3.2}

X - 60 = 1.175*3.2

X = 63.76

The interval containing the middle-most 76% of sample means is between 56.24 and 63.76.

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Each flower will have 10
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