The principal, P is $6 952.
Interest, R is 3.72% per year.
Time T = 16 years.
For simple interest, Amount A = P(1 + RT)
For compound interest, A = P(1+R)^T
a) If the money was saved as Simple Interest, Amount A
A = 6952 * (1 + 3.72% * 16)
A = 6952 * ( 1 + (3.72/100) * 16 )
A = 6952 * ( 1 + 0.5952)
A = 6952 * 1.5952
A = 11 089.8304
Amount if savings was simple interest, Amount at the end of 16 years =
$11 089.83
b) If the money was saved as Compound Interest, Amount A
A = 6952 * (1 + 3.72%)^16
A = 6952 * ( 1 + (3.72/100))^16
A = 6952 * ( 1 + 0.0372)^16
A = 6952 * 1.0372^16. Using your calculator.
A = 12 471.24735
Amount if savings was compounded interest, Amount at the end of 16 years =
$12 471.25
The question is was the amount saved as Simple Interest or Compound Interest?
It was not stated, but it is normal to use compound interest in real life.
I hope this helped.
C
Step-by-step explanation:
In my opinion by looking at the photograph I think its 6 in my opinion sorry if I'm wrong
Answer:
V = 34,13*π cubic units
Step-by-step explanation: See Annex
We find the common points of the two curves, solving the system of equations:
y² = 2*x x = 2*y ⇒ y = x/2
(x/2)² = 2*x
x²/4 = 2*x
x = 2*4 x = 8 and y = 8/2 y = 4
Then point P ( 8 ; 4 )
The other point Q is Q ( 0; 0)
From these two points, we get the integration limits for dy ( 0 , 4 )are the integration limits.
Now with the help of geogebra we have: In the annex segment ABCD is dy then
V = π *∫₀⁴ (R² - r² ) *dy = π *∫₀⁴ (2*y)² - (y²/2)² dy = π * ∫₀⁴ [(4y²) - y⁴/4 ] dy
V = π * [(4/3)y³ - (1/20)y⁵] |₀⁴
V = π * [ (4/3)*4³ - 0 - 1/20)*1024 + 0 )
V = π * [256/3 - 51,20]
V = 34,13*π cubic units
By adding all of the numbers on the the outside lines