We have three pythagoras:
4² + y² = z²
16² + y² = x²
x² + z² = 20²
Now let's think:
4² + y² = z²
y² = z² - 4²
16² + y² = x²
16² + z² - 4² = x²
x² + z² = 20²
16² + z²- 4² + z² = 20²
2z² = 20² - 16² + 4²
2z² = (2.10)² - (2^4)² + (2²)²
2z² = 2².10² - 2^8 + 2^4
z² = 2.10² - 2^7 + 2^3
z² = 200 - 128 + 8
z² = 208 - 128
z² = 80
z = √80
80 | 2
40 | 2
20 | 2
10 | 2
5 | 5
1
80 = 5.2^4
So
√80 = 4√5
z = 4√5
The volume of the second prism is 576 cubic centimeters. Since both prisms have the same height, I solved for the height using the data given with the first prism (I got 6 centimeters for the height). And then I calculated for the volume of the second prism.
We have been given prism J and prism K have the same volume. A cube J with height 10, length 4 and width 3 A right angled triangular prism K with breadth 10, height 3 and width w. We are asked to find width w of the prism K.
We will use formulas of volume of cuboid and volume of triangular prism.
Now we will equate both volumes as we are told that prism J and prism K have the same volume.
Therefore, the width w of prism K is 8 units.
Answer:
-0.66666666666
Step-by-step explanation:
Rewrite
i
2
as
−
1
.
6
⋅
−
1
Multiply
6
by
−
1
.
−
6
Answer:
B (-1, -1 1/2)
Step-by-step explanation:
You plot that and it aint there