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2 years ago

I NEED HELP ASAP PLEASEEEEEEEE!!!!!!!!!!

Mathematics

1 answer:

igomit [66]2 years ago

7 0

Step-by-step explanation:

In my opinion by looking at the photograph I think its 6 in my opinion sorry if I'm wrong

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The length of the guy why supporting a cell tower is 120 m the guy wire is anchored to the ground at a distance of 80 m from the

Katarina [22]

Complete Question

The length of the guy wire supporting a cell tower is 120 m. The guy wire is anchored to the ground at a distance of 80 m from the base of the tower to the nearest hundredth of a meter how tall is the tower?

Answer:

89.44m

Step-by-step explanation:

We solve this question using the Pythagoras Theorem

This is given as:

Hypotenuse² = Opposite ² + Adjacent ²

Hypotenuse = Length of the guy wire = 120m

Adjacent = Distance from the base of the tower = 80m

Opposite = Height of the building = x

Hence:

120² = x² + 80²

Collect like terms

x² = 120² - 80²

x = √120² - 80²

x = √(8000)

x = 89.4427191 m

Approximately the height of the tower is = 89.44m

6 0

3 years ago

Directions : Factor each of the following Differences of two squares and write your answer together with solution

N76 [4]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Factor each of the following differences of two squares and write your answer together with solution.

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\sf \: x ^ { 2 } - 36$

Rewrite $\sf\:x^{2}-36 as x^{2}-6^{2}$ . The difference of squares can be factored using the rule: $\sf\: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\boxed{ \boxed{ \bf\left(x-6\right)\left(x+6\right) }}$

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$\sf \: 49 - x ^ { 2 }$

Rewrite 49-x² as 7²-x². The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\sf \: \left(7-x\right)\left(7+x\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-x+7\right)\left(x+7\right) }}$

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$\sf \: 81 - c ^ { 2 }$

Rewrite 81-c²as 9²-c². The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\sf\left(9-c\right)\left(9+c\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-c+9\right)\left(c+9\right) }}$

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Rewrite m²n² - 1 as $\sf\left(mn\right)^{2}-1^{2}$ . The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .