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kotykmax [81]
3 years ago
11

A scale drawing of a building needs to be made using the scale 1 inequals=270270 ft. How tall will the building in the scale dra

wing be if the building is 27002700 ft​ tall?
Mathematics
1 answer:
nadezda [96]3 years ago
4 0

Answer:

and i oop

Step-by-step explanation:

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For the standard normal curve, find the z-score that corresponds to the 30th percentile. -0.47 -0.98 -0.53 -0.12
Nata [24]
We are looking for the Zo score that corresponds to the 30th percentile.
 We use the table for the standard normal distribution.
 From P (Z <Zo) = 0.3 we search for Zo.
 Then we look in the table for the value of Zo that corresponds to 0.3.
 Hence, the approximate value is -0.53.
 The option is the third
7 0
3 years ago
En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,
Lostsunrise [7]

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

4 0
3 years ago
Mrs rodriguez needs you to calculate the AREA of a circular pool with radius of 5 meters to help her figure out if it will fit i
Mila [183]
The formula for an area of a circle is A= pi(r)^2
so if you plug in 5 to r (because it’s the radius) you should get A= 78.5
3 0
3 years ago
If f(x)= x2+2x-10, what id f(-2)
Sindrei [870]
The answer is -18. Hope this helps.
6 0
2 years ago
Round 6.7086 to the nearest thousandth
Bingel [31]

\text {Hello! Let's solve this Problem!}

\text {To round to the nearest thousandth you must underline the thousandth place}\text {(which is 8), point an arrow to 6 (in the ten-thousandth place)}

\text {If the number is 5 or more you raise the score. Meaning you add 1 to the}\text {thousandth place. If the number is 4 or lower you keep the number the same.}

\text {6 is greater than 5. So this means you add 1 to 8 and it becomes 9. Every}\text {number behind it becomes 0.}

\text {Your Answer Would Be:}

\huge\boxed {\text {6.7090 or 6.709}}

\text {Best of Luck!}

7 0
3 years ago
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