Answer:
Given that an article suggests
that a Poisson process can be used to represent the occurrence of
structural loads over time. Suppose the mean time between occurrences of
loads is 0.4 year. a). How many loads can be expected to occur during a 4-year period? b). What is the probability that more than 11 loads occur during a
4-year period? c). How long must a time period be so that the probability of no loads
occurring during that period is at most 0.3?Part A:The number of loads that can be expected to occur during a 4-year period is given by:Part B:The expected value of the number of loads to occur during the 4-year period is 10 loads.This means that the mean is 10.The probability of a poisson distribution is given by where: k = 0, 1, 2, . . ., 11 and λ = 10.The probability that more than 11 loads occur during a
4-year period is given by:1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]= 1 - [0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.125110+ 0.125110 + 0.113736]= 1 - 0.571665 = 0.428335 Therefore, the probability that more than eleven loads occur during a 4-year period is 0.4283Part C:The time period that must be so that the probability of no loads occurring during that period is at most 0.3 is obtained from the equation:Therefore, the time period that must be so that the probability of no loads
occurring during that period is at most 0.3 is given by: 3.3 years
Step-by-step explanation:
Answer:
The slope is 1 and the y intercept is 1
Answer:
7,500 Pages
Step-by-step explanation:
So this printer can prink 25 pages in 1 (x) minute.
There are 60 minutes in an hour and we are waiting 5 hours, so 5x60 = 300 minutes.
Then you take the 300 and plug it in for x because that is how many minutes we are waiting for. Now your equation should look like this:
p(x) = 25(300)
Next you multiply 25 x 300 and you get 7,500 pieces of paper
Answer:
-1
Step-by-step explanation:
substitute x for 6 and y for 1
which will be 6-1+6
using BODMAS
6-(1+6)
6-7= -1
Answer:
Step-by-step explanation:
You have the following differential equation:
(1)
In order to find the solution to the equation, you can use the method of the characteristic polynomial.
The characteristic polynomial of the given differential equation is:
The solution of the differential equation is:
(2)
where m1 and m2 are the roots of the characteristic polynomial.
You replace the values obtained for m1 and m2 in the equation (2). Then, the solution to the differential equation is:
