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r-ruslan [8.4K]
3 years ago
7

What is 1.66666666667 rounded to the nearest tenth

Mathematics
1 answer:
Margarita [4]3 years ago
8 0
1.7
Since in the tenth place is a six, we round up to 7.
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Number one. Find the measure of ef. It will be in degrees. Correct answer will get brainliest.
Taya2010 [7]
EF will be the same as HG
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The area of a triangular garden can be no more than 120 square feet. The base of the triangle is 16 feet. What is the height of
almond37 [142]
Let us assume that the area of the garden is 120 sq.ft
It is given that base=16 ft
Area of Triangle = 1/2 * b * h
120 = 1/2 * 16 * h
h = 120 * 2/16
h = 120 * 1/8
h = 15 ft
Therefore, the height of the triangular garden is 15 ft
5 0
3 years ago
A circle has a diameter of 8 cm. An angle in the center of the circle creates an arc AB. That angle's measure is pi/4 rad. What
zhenek [66]

Answer:

3.14 cm

Step-by-step explanation:

From the question,

Applying

s = πdФ/360................... Equation 1

Where s = length of arc AB, d = diameter of the circle, Ф = angle at the center of the circle, π = pie

From the question,

Given: d = 8 cm, Ф = π/4 rad = 45°

Constant: π = 22/7

Substitute these values into equation 1

s = (22/7)(8)(45)/360

s = 3.14 cm.

Hence the lenght of arc AB = 3.14 cm

8 0
2 years ago
Why is the interest rate of a loan one of the most important things to consider when shopping around for loans?
lesantik [10]
I think c because it is right i think
3 0
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Read 2 more answers
Could you help me to solve the problem below the cost for producing x items is 50x+300 and the revenue for selling x items is 90
s344n2d4d5 [400]

Answer:

Profit function: P(x) = -0.5x^2 + 40x - 300

profit of $50: x = 10 and x = 70

NOT possible to make a profit of $2,500, because maximum profit is $500

Step-by-step explanation:

(Assuming the correct revenue function is 90x−0.5x^2)

The cost function is given by:

C(x) = 50x + 300

And the revenue function is given by:

R(x) = 90x - 0.5x^2

The profit function is given by the revenue minus the cost, so we have:

P(x) = R(x) - C(x)

P(x) = 90x - 0.5x^2 - 50x - 300

P(x) = -0.5x^2 + 40x - 300

To find the points where the profit is $50, we use P(x) = 50 and then find the values of x:

50 = -0.5x^2 + 40x - 300

-0.5x^2 + 40x - 350 = 0

x^2 - 80x + 700 = 0

Using Bhaskara's formula, we have:

\Delta = b^2 - 4ac = (-80)^2 - 4*700 = 3600

x_1 = (-b + \sqrt{\Delta})/2a = (80 + 60)/2 = 70

x_2 = (-b - \sqrt{\Delta})/2a = (80 - 60)/2 = 10

So the values of x that give a profit of $50 are x = 10 and x = 70

To find if it's possible to make a profit of $2,500, we need to find the maximum profit, that is, the maximum of the function P(x).

The maximum value of P(x) is in the vertex. The x-coordinate of the vertex is given by:

x_v = -b/2a = 80/2 = 40

Using this value of x, we can find the maximum profit:

P(40) = -0.5(40)^2 + 40*40 - 300 = $500

The maximum profit is $500, so it is NOT possible to make a profit of $2,500.

3 0
3 years ago
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