C r = (n!)/(r!(n-r)!)
9 C 3 = (9!)/(3!*(9-3)!)
9 C 3 = (9!)/(3!*6!)
9 C 3 = (9*8*7*6!)/(3!*6!)
9 C 3 = (9*8*7)/(3!)
9 C 3 = (9*8*7)/(3*2*1)
9 C 3 = (504)/(6) 9 C 3 = 84
Answer:

Step-by-step explanation:
We are given the function:

Remember that by the definition of absolute value:

Our absolute value is:

First, we will find when it becomes 0. Set the equation equal to 0:

Solve for <em>x: </em>
<em />
<em />
<em />
So, we can see that for all values greater than <em>x </em>= 5/2, 2x - 5 is positive.
For all values less than <em>x </em>= 5/2, 2x - 5 is negative.
Therefore (the positive case go above, and the negative case go below):

Finally, we can add a three:

Simplify if desired:

The answer is 416 multipy all sides