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aalyn [17]
3 years ago
9

Can someone please help me

Mathematics
1 answer:
mixas84 [53]3 years ago
5 0

Answer:

1/3

Step-by-step explanation:

The slope of a line is rise over run, aka. rise/run. You will need to "rise" 1 unit up and "run" three units to the right to reach the next point.

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Please help me!!!!!!!!!​
lara [203]

Answer:

The answer to your question is:

Domain [0, 8)

Range [-3, 1]

f(0) = -3

Step-by-step explanation:

Domain: is the possible values that the "x" can take

Range: are the values that take the function when is evaluated by the independent variable (x).

For this example:

                            Domain [0, 8)   close is zero and open in 8

                            Range [-3, 1]     close in both sides

                           f(0) = -3

8 0
3 years ago
If triangle RST and triangle XYZ are similar, which statement must be true?
Evgen [1.6K]
If triangle RST and triangle XYZ are similar, the statement that must be true is :
Angle R equals angle X

Triangle      R             S                    T
Triangle      X             Y                    Z

those three angles will be similar in this case

hope this helps
4 0
3 years ago
Read 2 more answers
6x-3y =15<br><br><br> (System of Equations)
Vadim26 [7]

Answer:

x= 5/2 + y/2

Step-by-step explanation:

So yeah... that's the answer

6 0
3 years ago
A triangular window pane has a base of 30 inches and a height of 24 inches.What is the area of the window pane?
densk [106]

54 or it 180 i got 54 by adding 30 and 24in and got 180 by multiplying

8 0
3 years ago
Read 2 more answers
let a = (a1, a2) and b = (b1, b2) and c = (c1,c2) be three non zero vectors. if a1b2 - a2b1 is not equal to 0. then show three a
Ksenya-84 [330]

Consider the contrapositive of the statement you want to prove.

The contrapositive of the logical statement

<em>p</em> ⇒ <em>q</em>

is

¬<em>q</em> ⇒ ¬<em>p</em>

In this case, the contrapositive claims that

"If there are no scalars <em>α</em> and <em>β</em> such that <em>c</em> = <em>α</em><em>a</em> + <em>β</em><em>b</em>, then <em>a₁b₂</em> - <em>a₂b₁</em> = 0."

The first equation is captured by a system of linear equations,

\begin{cases}c_1 = \alpha a_1 + \beta b_1\\ c_2 = \alpha a_2 + \beta b_2\end{cases}

or in matrix form,

\begin{pmatrix}c_1\\c_2\end{pmatrix} = \begin{pmatrix}a_1&b_1\\a_2&b_2\end{pmatrix}\begin{pmatrix}\alpha\\\beta\end{pmatrix}

If this system has no solution, then the coefficient matrix on the right side must be singular and its determinant would be

\begin{vmatrix}a_1&b_1\\a_2&b_2\end{vmatrix} = a_1b_2-a_2b_1 = 0

and this is what we wanted to prove. QED

3 0
3 years ago
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