Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
The intersections of the equations represent the times when the bird and the ball are at the same height.
8t+20=-16t^2+65t
16t^2-57t+20=0, using the quadratic equation for expediency:
t=(57±√4529)/32 and since we know t>0
t≈3.88 seconds (at a approximate height of 51 feet)
Answer:
50 ft
Step-by-step explanation:
The sum of length and width is half the perimeter, so ...
L + W = P/2
L = P/2 - W = (180 ft)/2 - 40 ft = 50 ft
The length of the garden is 50 ft.
Answer:
5x+2
Step-by-step explanation:
Ok so the expression 5(x+2) is not 5x+2 because you have to use the distributive property. So with that being said:
5(x+2)=5 times x and 5 times 2
so the realest answer is 5x+10 instead of 5x+2
Answer:
11
Step-by-step explanation:
-6-5
+11
Hope it is helpful